Q2 ĀC + AC + B By using NAND gates only, implement the Boolean expression
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- Implement the Logic expression using only NOT and two-input NAND gates. A+B+C+DDraw a Logic Circuit Diagram by implementing Full Adder in product of sumsAn equation in reduced SOP form, is F=AB+B'C+A'C'. I need to draw a logic circuit F using NOT/AND/OR and logoc circuit F using all NAND gates. Thank you for the help. I understood the previous types of gates but I am confused on how to draw these circuits.
- Using the Boolean rules, delermine the outputs of the logic circuits below: a) A b). c) c). B d) ADraw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FFor the logic gate network shown below, select which of the following expressions is the right one. Note that, the answer None of the above may sometimes be the correct response. A B D O C=A.B O C=(A.B) C = A.B C = A.B None of the above Not answered O Doc C
- Problem: Derive the logic expressions for a circuit that compares two unsigned numbers: X = x2x1xo and Y = = y2y1yo and generates three outputs: XGY, XEY, and XLY. One of these outputs is set to 1 to indicate that X is greater than, equal to, or less than Y, respectively.Logic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions. Task 2: 4 INPUT PRIORITY ENCODERa) Write the truth table.b) Find the outputs in terms of min terms using minimal expression.c) By using K map, find the simple/simplest expression of theoutputs.d) Draw the circuit diagram. (Simulation design will be accepted.)e) Simulate the circuit & explain your results. (Please do notdesign separate simulations for each output. You should design ONEsimulation including all inputs and outputs.)T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of these
- 00 0 Output Transitions QN+1 Flip-Flop Inputs K 010 001 Option QN 101 011 B 1. 111 100 C 110 0. In the processes for ring counter design calculate the values for the state table below, for the "option" section enter A or B or C or D state table pesent state next state Option q2 q1 q2 q1 q0 q2 q1 q0 1 17 25 33 41 49 57 65 10 18 26 34 42 50 58 66 3. 11 19 27 35 43 51 59 67 4. 12 20 28 36 44 52 60 68 13 21 29 37 45 53 61 69 14 22 30 38 46 54 62 70 15 23 31 39 47 55 63 71 8 16 24 32 40 48 56 64 72Using Boolean theorems, simplify the output expression for the circuit in the figure. Show all the steps used to simplify the expression.Simplify the following Boolean expressions using Karnaugh Map and draw the logic circuits. f = wxyz + wxyz + wxyż + wxỹz + wxyz + wxyz + wxỹz + wãyz