None Q2/ A100 X100 X8 mm angle is welded to a gusset plate,find L1 and L2.L2P1+75 mm200 KN25 mmP2 -L1

Given:- force=200kN To find:- L1 L2

Answered: Q2/ A100 X100 X8 mm angle is welded to…

Engineering

Civil Engineering

Q2/ A100 X100 X8 mm angle is welded to a gusset plate,find L1 and L2.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter4: Compression Members

Section: Chapter Questions

Problem 4.6.3P

See similar textbooks

Similar questions

A76 x 76 x6 mm angular section shown is welded to an 8 mm thick gusset plate. The length L1 is 65 mm, L2 is 125 mm, and the cross sectional area of the angle is 929 sq.mm. Fy-248MPA and Fu -400MPA. Gusset Plate Alowable Sresse Alowable tensle stress igross ara)0.00 Alowable tereile stres net area)0SOF. Allowable shear stress (net ares)0.30F. Determine the value of P based on net area using a strength reduction coefficient of 85% O 138.24 KN O 140.14 kN O 157.93 kN O 304.00 N Next
Problem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4 - 22 mm diameter bolts. 12 mm bolts T12 mm te12 mm P 300 75 75 75 Edge distances = 75 mm %3D dnole for tensile and rupture = dp +3 mm %3D dnole for bearing strength for Lec = d + 1.5 mm Fy = 248 MPa Fu = 400 MPa %3D En 330 MPa %3D Use LRFD design method. Determine the design strength due to tensile rupture strength of plates. (kN)
sted ingid 250MM B k steel bar bolt AUR rigid bar 12 mm thick 8 mm Brass 350mm Jointd 16 mene thick 350mm JointB 250 mm Xg = 20x10% Eg = 90 G Pa -6 A, = 12x10/0 Es = 200 G Pa thickness> 16 mm 8 mm bolt %3D 12 mmi thick shear strength f bolf bearing streng th of holt= 100 la 50 MPa %3D Assume no failure will take place in steel or brass. Temperature chauge brass steel on Temperature change on Determine thai can be applied to system - the max
أ.د. رمضان المبروك A PL170mm x 10mm tension member is welded to a gusset plate as shown in Figure below. The steel is A36. Assume that Ae = Ag and compute the following. %3D fy = 250 MPa & f, = 400 MPa %3D %3D PL 170mmx10mm a. The design strength for LRFD. . The allowable strength for ASD. roblem (4):
Internal effortsfeatures on a 750 mm sheet wide (made of ASTM A36 steel) were determined using a software basic structure analysis. The effort characteristic requester from a usage overhead is equal to 1260kN. Calculate the thickness needed for the plate? Adopt fyk = 250 MPa and fuk = 450 MPa.Please help Expert sir
Take R as 70
Material Strengths: Fy = 248 MPa, F = 400 MPa For the two lines of bolt holes, the pitch is the value that will give a net area DEFG equal to the one along ABC. The diameter of the holes is 22 mm. The thickness of the plate is 12 mm. Determine the LRFD design tensile strength based on yielding on gross area. D A to 50 1 ÓB 50 50 ic O 410 kN O 464 kN O 446 kN O 401 KN F IG Pitch Pitch KISS|Y
Asap pls
I the Design the reinforcements of the given T beam below. bf=900mm bw=420mm tf=120mm d=550mm d'=80mm fc'=34MPA fy=415MPA USE NSCP 2015 mm2 A.Mu = 1400KN-m, As = mm2 B.Mu = 1700kN-m, As = mm2, As' = CS Scanned with CamScanner
Bolted and Riveted Connections From the bolted connection shown, the diameter of bolts is 18mm0 with the hole diameter equal to 3mm bigger than the bolt, the angular section is 100 x 75 x 8 mm, with an area of 1340 mm2. Thickness of the gusset plate is 9mm. The gusset plate and angle arc A36 steel with Fy = 250 MPa and Fu = 400 MPa. Determine the tensile capacity of the connection based on gross area. Determine the tensile capacity of the connection based on effective net area using a reduction factor of 0.85. Determine the tensile capacity of the connection based on gross area.
H1
A C8x11.5 single channel section us bolted to a gusset plate with M22 bolts. Assume A36 steel, 5.6 mm thick web for the channel and an 8mm gusset plate. U=0.80 The channel has a gross area of 2181 mm^2. The bolts have a shear stress of 457 Mpa. What is the design tensile strength due to gross yielding (kN)?