Q2) A 220-V, 3-op, 4-pole, 50-Hz, Y-connected induction motor is rated 3.73 kW.The equivalent circuit parameters are:R1 0.45 2, X1 = 0.8 2; R2' 0.4 S2, X2' 0.8 2, Xm = 30 2The stator core loss is 50 W and rotational loss is 150 W. For a slip of 0.04, find (i) input current (ii) p.f.

i) To find the input current of the motor, we need to calculate the total impedance of the motor at…

Answered: Q2) A 220-V, 3-op, 4-pole, 50-Hz,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

The series field winding of a 170 kW, 250 V, 1450 rpm compound generator has a resistance of 0.00306 ohm. What will be the required resistance (in Ohm) of a noninductive diverter that will bypass 27 percent of the total armature current? "
None
For the design we assuming following parameters 1) winding : Lap 2) simplex 3) Number of slots : 16 , single turn coil with 2 conductors per slot 4) Number of poles = 4
Solve it fast fast fast plz
Q4) What is the effect in series motor if you assume V = Eb , with low resistance fielding winding ? a) b) The given information about series motor on full – load (with that the flux is proportional to the field current) is a ) takes ( 78A) and runs at (850 r.p.m) , the series winding resistance is (0.04 2) , with diverter in parallel with the field winding is a (0.18 2) and the armature resistance is (0.09 S2). ( 220 V Neglected the iron, friction and windage losses. Determine the efficiency , speed when developing full load torque ,the maximum efficiency .
With the aid of diagrams describe the basic topology of a wound field 3 phase synchronous generator and outline the relationship between the excitation voltage and rotor current. Q2 (a) (b) Outline with the aid of a suitable diagram the necessary power conversion stages required to interface a small permanent magnet (PM) generator to a stand alone DC system. A star connected 3 phase wound field synchronous generator with a synchronous reactance of 20 N is connected to a 6.6 kV (phase voltage) grid and supplies 1.5 MW at 0.95 lagging power factor at its terminals. Calculate the phase current and resultant voltage across the synchronous reactance (Vxs), and from a scaled phasor diagram graphically determine the required excitation voltage (Eph) and load angle (8). (c) The load is now increased to 3 MW with the Excitation Voltage kept constant. Using the phasor diagram drawn in part (c) graphically determine the resultant phase current, power factor and load angle. (d)
A three-phase star-connected alternator working at 1400 KVA,50 Hz, 2300 V, has an armature dc resistance of 0.15 2. Assume the ac resistance is 1.4 times the dc resistance. A field current of 75 A produces a short circuit current of 360 A and for the same field current the open circuit voltage is 1000 V. Determine a) Synchronous reactance of the machine b) Full load regulation at 0.9 leading c) Power angle a) b)
Q2. a) A 415V, 50Hz, 3-phase induction motor supplies its rated power to a load. The rated speed of the motor is 980 rpm. b) Two synchronous generators, G2 and G2, are connected parallelly supplying a load. Generator G1 has a no-load frequency of 50.5 Hz and a slope of 300 MW/Hz. Generator G2 has a no-load frequency of 50.2 Hz and a slope of 500 MW/Hz. The load consumes 250 MW real power. (i) At what frequency does this system operate, and how much power is supplied by each of the two generators? (ii) An additional 100 MW load is added to this power system. What is the new system frequency, and how much power do G1 and G2 supply? (iii) The governor set point of G2 is changed to control system frequency back to 50 Hz. Determine the G2 governor set point.
The armature of a 400V, 6-pole, 25 Hz single-phase series motor is lap-wounded with 504 conductors Motor field winding has effective resistance and leakage reactionance are 0.06 22 and 0.05 12, respectively and has 18 turns. However, the armature winding has a leakage reactance of 0.04 12 and negligible resistance. At rated motor current of 300A, the flux per pole is 0.05 Wb, the short circuit current is 50A and the equivalent current to iron losses is 40A. Find motor speed , torque and efficiency at rated current .
Q.14. What is slip in an induction motor? Q.15. What is the value of slip at start in an induction motor?
Solove for the Equivalent Resistance at CE

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Q2) A 220-V, 3-op, 4-pole, 50-Hz, Y-connected induction motor is rated 3.73 kW. The equivalent circuit parameters are: R1 0.45 2, X1 = 0.8 2; R2' 0.4 S2, X2' 0.8 2, Xm = 30 2 The stator core loss is 50 W and rotational loss is 150 W. For a slip of 0.04, find (i) input current (ii) p.f.