Q12 In an Otto cycle air at (15 °C) and (1.05 bar) is compressed adiabatically until the pressure is (13 bar). Heat is added at constant volume until the pressure rises to 23 (35 bar). Calculate (a) the compression ratio. (b) air standard efficiency. (c) mean effective pressure for the cycle. Take Cv = 0.717 Kj/Kg.K and R = 0.293 Kj/Kg.K. Answers: (a) 16 (b) 51.1 % (c) 550.6KN/m²

At the beginning of the compression process of an air-standard Diesel cycle, p₁ = 95 kPa and T₁ = 300 K. The maximum temperature is 2100 K and the mass of air is 12 g. For a compression ratio of 18, determine: (a) the net work developed, in kJ. (b) the percent thermal efficiency. (c) the mean effective pressure, in kPa.

Air at 100 kPa, 37°C enters an ideal Otto cycle. The peak pressure and temperature in the cycle are 4.6MPa and 1927 °C, respectively. The compression ratio is 6.414. Using an air-standard analysis, determine: a. The internal energy at each part of the cycle: U₁ = U₂ = Uz = U4 = b. the net work per unit mass b. the cycle thermal efficiency= = kJ/kg kJ/kg kJ/kg kJ/kg kJ/kg

At the beginning of the compression process of an air-standard Otto cycle, p1 = 100 kPa,  T1 = 290 K, V1 = 400 cm3. The maximum temperature in the cycle is 2200 K and the compression ratio is 8. Determine the (a) thermal efficiency; and (b) mean effective pressure, in bar. (c) Solve on a cold air-standard basis with constant specific heats.

Refer to the following figure for an Air Standard Otto Cycle. At the beginning of compression stroke: • Volume is 0.45 m³; • Pressure is 1 bar; and • Temperature is 30°C; At the end of the compression stroke: • Pressure is 11 bar; 210 kJ of heat is added at constant volume. Assuming the cycle is reversible. T(K) = 273 +T(°C); Determine the following to the approximation. • Pressures at point 4 bar • Swept Volume= m • Maximum Temperature of the cycle = °C • Net work output of the cycle = kJ • Heat Rejected from the cycle = kJ • Thermal efficiency of the cycle = • Mean Effective Pressure = bar % p (bar) 21.48 11 V₁ = 0.45 m³ Adiabatics → V (m³)

Air enters the compressor of an ideal air-standard Brayton cycle at 88 kPa, 280 K, with a volumetric flow rate of 1225 m3/s. The compressor pressure ratio is 12. The turbine inlet temperature is 1225 K. Take Specific heat at constant pressure and constant volume for air as 1.006 kJ/kg K and  0.717 kJ/kg K respectively. Calculate the thermal efficiency of the plant to one decimal place and include the correct unit (percentage). Use cold air standard assumption

3The rate of heat addition to an ideal air-standard Brayton cycle is 1.0 x 107 Btu/h. The pressure ratio for the cycle is 12 and the minimum and maximum temperatures are 520°R and 2800°R, respectively.Determine:(a) the percent thermal efficiency of the cycle.(b) the mass flow rate of air, in lb/h.(c) the net power developed by the cycle, in hp.

In an Otto cycle air at 27 degree centigrade and 1 bar is compressed adiabatically to 12bar. Heat addition occurs at constant volume and pressure rises to 30bar. Determine the air standard efficiency, compression ratio. Assume Cv= 0.717 KJ/kgK for air.

Air enters the compressor of an ideal air-standard Brayton cycle at 100 kPa, 283 K, with a volumetric flow rate of 5 m3/s. The compressor pressure ratio is 8:1. The turbine inlet temperature is 1400 K. Take Specific heat at constant pressure and constant volume for air as 1.006 kJ/kg K and  0.717 kJ/kg K respectively. Calculate the compressor exit absolute temperature to one decimal place and place the correct unit. Use the cold air-standard assumption.

Required information Problem 09.015 - 3-Step Air-Standard Cycle with Constant Specific Heats - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS An air-standard cycle with constant specific heats at room temperature is executed in a closed system with 0.003 kg of air and consists of the following three processes: 1-2 v= Constant heat addition from 95 kPa and 17°C to 380 kPa 2-3 Isentropic expansion to 95 kPa 3-1 P = Constant heat rejection to initial state The properties of air at room temperature are cp = 1.005 kJ/kg-K, cy= 0.718 kJ/kg-K, and k = 1.4. Problem 09.015.b - Net Work for Constant Heat Capacity Air-Standard Cycle Calculate the net work per cycle, in kJ. (You must provide an answer before moving on to the next part.) The net work per cycle is kJ.