Kindly solve it . Jan 2021Q11. A simple harmonie oscillator consists of a block of mass 1.45 kg attached to a spring of springconstant 54.4 N/m. When t-0.670 s, the position of the block is x-0.0565 m (from the equilibriumposition) and its veloeity is v=0.342 m/s.A. What is the angular frequeney of the oscillation?B. What is the amplitude of the oseillation?C. What is the phase constant for the oscillation?D. What was the velocity at t-0?

SOlution: Given that m = 1.45 kg k = 54.4 N/m t =0.67s , x = 0.0565 m v = 0.342 m/s

Q11. A simple harmonic oscillator consists of a block of mass 1.45 kg attached to a spring of spring constant 54.4 N/m. When t-0.670 s, the position of the block is x-0.0565 m (from the equilibrium position) and its velocity is v=0.342 m/s. A. What is the angular frequeney of the oscillation? B. What is the amplitude of the oscillation? C. What is the phase constant for the oscillation? D. What was the velocity at t=02