Q1). The following consecutive readings were taken along a straight line from station (11+090) to station (12+015). The instrument has been changed after third, (3 fifth, eighth and welfth readings. The readings are as bellows: 0.68 D. 0.680, 1.455, 1.855, 2.330, 2.885, 3.380, 1.055, 1.680, 2.265, 3.540, 0.835, 0.945, 1.530 and 2.250, first and last point are a bench marks having elevations 50.25m and 50.81 m respectively. 44.8 1- Draw page of level book and enter the above data. 2- Find elevation of points by height of instrument method. 3- Check your calculation. 4- Determine the gradient of the line joining the first and last point. 5- Determine loop closure and adjust calculated elevations. -5.408

Q1). The following consecutive readings were taken along a straight line from station (11+090) to station (12+015). The instrument has been changed after third, (3 fifth, eighth and welfth readings. The readings are as bellows: 0.68 D. 0.680, 1.455, 1.855, 2.330, 2.885, 3.380, 1.055, 1.680, 2.265, 3.540, 0.835, 0.945, 1.530 and 2.250, first and last point are a bench marks having elevations 50.25m and 50.81 m respectively. 44.8 1- Draw page of level book and enter the above data. 2- Find elevation of points by height of instrument method. 3- Check your calculation. 4- Determine the gradient of the line joining the first and last point. 5- Determine loop closure and adjust calculated elevations. -5.408

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A transit with a stadia interval factor of 100.12 was set at C on the line between points A and B, the following stadia readings were observed. (draw the Instrument set up) *INserted Photo*
Q.1 A line of level is run from B.M.1 (elevation=103.00m) to B.M. 2(elevation=107.00m). The field observations were recorded as given below: Station В.S I.S F. S Remarks 1 1.95 В.М. 1 0.65 3 2.60 1.45 -1.90 -1.60 0.55 6. 0.50 В.М. 2 Reduce the level of point 2, 3, 4 and 5, determine the total error of closure, and adjust the values.
P 0.25in— I SR E0E L OV ER SRRV R fatima jappar / < 9:590 4cludl 21.06.21 O O > %
Q.1 A line of level is run from B.M .1 (elevation=102.00m) to B.M. 2(elevation=106.00m). The field observations were recorded as given below: Station В. S I.S F. S Remarks 1 1.95 В.М. 1 2 0.65 2.60 1.45 4 -1.90 -1.60 5 0.55 6 0.50 В.М. 2 Reduce the level of point 2, 3, 4 and 5, determine the total error of closure, and adjust the values.
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Q1). The following consecutive readings were taken along a straight line from station (11+090) to station (12+015). The instrument has been changed after third, fifth, eighth and welfth readings. The readings are as bellows: (3 0.68 0.680, 1.455, 1.855, 2.330, 2.885, 3.380, 1.055, 1.680, 2.265, 3.540, 0.835, 0.945, 1.530 and 2.250, first and last point are a bench marks having elevations 50.25m and 50.81 m respectively. 44.8 1- Draw page of level book and enter the above data. 2- Find cleve on of pointe hy height of instrument method. 3- Check your calculation. 4- Determine the gradient of the line joining the first and last point. 5- Determine loop closure and adjust calculated elevations. -5.408
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In the area of settlement in the area, the background readers are lost and the front and all the verbal points for one of the settlement operations and then very valuable if you know that the level of station No. 10 is equal to 220.800m?