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Q1. Consider strings initialized as
char* a = "Welcome to House";
char b[] = " Welcome to House";
Are a and b different?
Why?
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- String Manipulation In this question, you will be implementing the following functions int findChar(char * str, char c); Searches for the character c in the string str and returns the index of the character in the string. If the character does not exist, returns -1 int replaceChar(char * str, char c1, char c2); Searches for the character c1 in the string str and if found, replace it with c2.The function returns the number of replacements it has performed. If the character does not exist, returns 0. int removeChar(char * str1, char * str2, char c); Creates a copy of str1 into str2 except for the character c that should be replaced with ‘*’ For example, if str1=”Hello World” and c=’l’ then the function should make str2=”He**o Wor*d” int isPalindrome(char * str) Checks to see if a string is Palindrome(reversible). If it is, returns 1, otherwise returns 0. A palindrome string reads similarly from left to right and from right to left like madam, level, radar, etc. int reverseString(char…Number guessing Game Write a C program that implements the “guess my number” game. The computer chooses a random number using the following random generator function srand(time(NULL)); int r = rand() % 100 + 1; that creates a random number between 1 and 100 and puts it in the variable r. (Note that you have to include <time.h>) Then it asks the user to make a guess. Each time the user makes a guess, the program tells the user if the entered number is larger or smaller than its number. The user then keeps guessing till he/she finds the number. If the user doesn’t find the number after 10 guesses, a proper game over message will be shown and the actual guess is revealed. If the user makes a correct guess in its allowed 10 guesses, then a proper message will be shown and the number of guesses the user made to get the correct answer is also printed. After each correct guess or game over, the user decides to play again or quit and based on the user choice, the computer will make…C ++ Lab Cross Out Write a program that will ask for a sentence and letters to cross out. It should then print the sentence with the given letters changed to ‘X’ and it should say how many letters were crossed out. It should work regardless of case.
- #include <iostream>#include <string>#include <climits> using namespace std;class BalancedTernary { protected: // Store the value as a reversed string of +, 0 and - characters string value; // Helper function to change a balanced ternary character to an integer int charToInt(char c) const { if (c == '0') return 0; return 44 - c; } // Helper function to negate a string of ternary characters string negate(string s) const { for (int i = 0; i < s.length(); ++i) { if (s[i] == '+') s[i] = '-'; else if (s[i] == '-') s[i] = '+'; } return s; } public: // Default constructor BalancedTernary() { value = "0"; } // Construct from a string BalancedTernary(string s) { value = string(s.rbegin(), s.rend()); } // Construct from an integer BalancedTernary(long long n) { if (n == 0) { value = "0"; return; } bool neg = n < 0; if (neg) n = -n; value = ""; while (n !=…C++ Write an expression to access the last character of a string class object str (not C-string)Complete the function empty which returns true if s1 has a length of 0. You may not use any library functions from . cstrings.cpp #include using namespace std; bool empty(const char* s) { 1 4 5 7 8 }
- s = "abab" h 55m Left Substrings in s are { 'a', 'b', 'a', 'b', 'ab', 'ba', 'ab', 'aba', 'bab', 'abab'}. By deleting one "a" and one "b", the string becomes "ab" or "ba" and all of its substrings are distinct. This required 17. String Reduction 2 deletions. Given a string, reduce it in such a way that all of its substrings are distinct. To do so, you may delete any characters at any ALL index. What is the minimum number of deletions needed? Function Description Complete the function getMinDeletions in the editor below. Note: A substring is a contiguous group of 1 or more characters within a string. getMinDeletions has the following parameter(s): Example string s: the given string 8 S = "abab" Returns: int: the minimum number of deletions required Substrings in s are { 'a', 'b', 'a', 'b', 'ab', 'ba', 'ab', 'aba', 'bab', 'abab'}. By deleting one "a" and one "b", the string becomes "ab" or "ba" and all of its substrings are distinct. This required Constraints 2 deletions. 10 1sns 105…* A = [2-31; 20 -1; 1 4 5], then det(A) is 49 39 27 33 Other:c++ coding language I need help with part B and C please. If you are unable to do both, then PLEASE prioritize part C. I am really stuck and really can use the help. This is the code for c that was provided in order to guide me: const int N =31; // N parking spaces bool parking[N]; // the garage void EmptyTheLot(bool parking[], int N) { for(int i=0; i<N; i++) p[i]=false; // empty space } // returns -1 if no space found, //otherwise it returns 0<=i<N for a valid space. int FindSpace(int PlateNumber, bool parking[], int N) { // ????? } main() { EmptyTheLot(parking, N); // start with an empty parking garage. // get plate numbers and fill lot. }
- C++ PROGRAMMING Create a C++ program that accepts an English sentence and converts it to Pig Latin. The rules of Pig Latin are as follows: If the word starts with a vowel, add the word "yay" in the end. If the word starts with a consonant, move the first letter of the word in the end and add "ay" in the end. If the word starts with a capital letter, follow the rule and convert the first letter of the converted Pig Latin word into a capital letter. (i.e. Hello -> ElloHay) If there are numbers in the sentence, they should not be translated. A word with a combination of letters and numbers will not be tested. Spacing and punctations must be preserved. Sample Input: A quick brown fox jumps over the 100 lazy dogs. Expected Output: Ayay uickqay rownbay oxfay umpsjay overyay hetay 100 azylay ogsday.#include <iostream>#include <string>#include <climits>using namespace std; class BalancedTernary {protected:// Store the value as a reversed string of +, 0 and - charactersstring value; // Helper function to change a balanced ternary character to an integerint charToInt(char c) const {if (c == '0')return 0;return 44 - c;} // Helper function to negate a string of ternary charactersstring negate(string s) const {for (int i = 0; i < s.length(); ++i) {if (s[i] == '+')s[i] = '-';else if (s[i] == '-')s[i] = '+';}return s;} public:// Default constructorBalancedTernary() {value = "0";} // Construct from a stringBalancedTernary(string s) {value = string(s.rbegin(), s.rend());} // Construct from an integerBalancedTernary(long long n) {if (n == 0) {value = "0";return;} bool neg = n < 0;if (neg)n = -n; value = "";while (n != 0) {int r = n % 3;if (r == 0)value += "0";else if (r == 1)value += "+";else {value += "-";++n;} n /= 3;} if (neg)value = negate(value);} // Copy…remove_substring_from_string(s, substr): This function takes two strings s and substr as input. It creates a new string from the original string s by removing all instances, if any, of the string substr, and then returns the new string. >>> remove_substring_from_string("Python is best language except for C++. except for C++") 'Python is best language. '