Q1. A ball at 1200 K is allowed to cool down in air at an ambient temperature of 300 K. Assuming heat is lost only due to radiation, the differential equation for the temperature of the ball is given by OP = -2.2067x10-12 (0ª – 81×10*) dt 0(0) = 1200K where 0 is in K and t in seconds. Find the temperature at t=480 seconds using the Runge-Kutta 4th order method. Assume a step size of h=120 seconds.
Q1. A ball at 1200 K is allowed to cool down in air at an ambient temperature of 300 K. Assuming heat is lost only due to radiation, the differential equation for the temperature of the ball is given by OP = -2.2067x10-12 (0ª – 81×10*) dt 0(0) = 1200K where 0 is in K and t in seconds. Find the temperature at t=480 seconds using the Runge-Kutta 4th order method. Assume a step size of h=120 seconds.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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