I need the answer quickly Q1) a-The electrical conductivity and electron mobility for aluminum are* 3.8X10' (2.m)' and 0.0012 m?/V.s, respectively. Calculate the Hall voltage foran aluminum specimen that is 15 mm thick for a current of 25 A and amagnetic field of 0.6 tesla (imposed in a direction perpendicular to the current).b-An Iron rod of length I and a cross section A has to be replaced by anotherrod (where the length of the second rod is half of the first and its cross section isone-third of the first). Find the material which has to be used in the second rodto equalize the resistance of the first.

As per company guidelines we can solve only first question post another question separately

Q1) a-The electrical conductivity and electron mobility for aluminum are .8X107 (2.m) and 0.0012 m/V.s, respectively. Calculate the Hall voltage for n aluminum specimen that is 15 mm thick for a current of 25 A and a nagnetic field of 0.6 tesla (imposed in a direction perpendicular to the current). -An Iron rod of length I and a cross section A has to be replaced by another od (where the length of the second rod is half of the first and its cross section is

Q1) a-The electrical conductivity and electron mobility for aluminum are .8X107 (2.m) and 0.0012 m/V.s, respectively. Calculate the Hall voltage for n aluminum specimen that is 15 mm thick for a current of 25 A and a nagnetic field of 0.6 tesla (imposed in a direction perpendicular to the current). -An Iron rod of length I and a cross section A has to be replaced by another od (where the length of the second rod is half of the first and its cross section is

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter12: Electronic Control Devices

Section: Chapter Questions

Problem 14RQ

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