(ABA) B= A+B xy=xy+xy ((AB)+(AB)A) B Q1/A D AAB+ ((A+B)A) B=> 0+ (AA+AB) B ABB (AB) B+(AB) B AB+(A+B) B=> AB+ A B+B AB + ( A +1) B => AB+ B = (A+B) (B+B) A 4B Bo A+B= (ABA)B Q1: (A) Prove the following Boolean equation using the theorems of Boolean algebra. (10 marks) A+B (ABA) B

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Please note the two images. The first image is the question, and the second is the solution, but I'm not sure about the solution, so I need to confirm the solution or correct it, and explain the steps where it came from. Thank you.
(ABA) B= A+B
xy=xy+xy
((AB)+(AB)A) B
Q1/A
D
AAB+ ((A+B)A) B=> 0+ (AA+AB) B
ABB (AB) B+(AB) B
AB+(A+B) B=> AB+ A B+B
AB + ( A +1) B => AB+ B = (A+B) (B+B)
A 4B
Bo
A+B=
(ABA)B
Transcribed Image Text:(ABA) B= A+B xy=xy+xy ((AB)+(AB)A) B Q1/A D AAB+ ((A+B)A) B=> 0+ (AA+AB) B ABB (AB) B+(AB) B AB+(A+B) B=> AB+ A B+B AB + ( A +1) B => AB+ B = (A+B) (B+B) A 4B Bo A+B= (ABA)B
Q1: (A) Prove the following Boolean equation using the theorems of Boolean algebra. (10 marks)
A+B (ABA)
B
Transcribed Image Text:Q1: (A) Prove the following Boolean equation using the theorems of Boolean algebra. (10 marks) A+B (ABA) B
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