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- A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.
- A capacitor in series with a 20-KO resistance across a 10 V ac source. What size C is needed for equal voltage across R and Xc at frequency of 100 Hz and 100 KHz.A series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.1)The value of the capacitance reactive power in VAR is? /2) The value of the capacitor in micro farad is?
- 1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.An inductor and a resistor are in series with a sinewave voltage source. The frequency is set so that the inductive reactance is equal to the resistance. If the frequency is increased, then options: Voltage across the inductor= Source Voltage Voltage across the inductor> Voltage across the resistor Voltage across the inductor= Voltage across the resistor Voltage across the resistor > Voltage across the inductor5. What capacit in series with a 1.5-k2 resistor will draw 50 mA from a 120-V, 60-Hz source?
- Figure 2 shows three "LC" circuits, two of them with capacitors of capacitance "C" and the three with inductance coils "L", the three circuits are coupled by means of two capacitors "Cc" capacitors. inductance "L", the three circuits are coupled by means of two capacitors of capacitance "Cc". The currents circulating through each mesh are those indicated in the figure: "I1", "I2" and "I3". Using Kirchhoff's law for voltages and taking into account the definition of current I = -dQ/dt, find the system of coupled equations of the system and then find the angular normal frequencies of the system.I is the voltage source current and 13 A is the value of current at Resistor and capacitor node.Please calculate voltage source current and capacitor current.i. The equivalent inductance between A and B of the circuit shown in figure B2 is 4.67mH. Find the value of unknown inductor, L. L1 L4 2mH 1.5mH L3 7mH L5 14mH A LT -4.67MH B Figure B2 ii. Consider a coil with inductance, L'. Number of turns, 'N' and length of the coil, l". If the length of the coil is halved and number of turns is doubled, what will be the new value of inductance?