Q.4) Two wooden boards, each weighing 15 lb, are fastened together and supported by ball-and-socket joints at A and F and by wire BH. Compute the tension in wire BH if the system is in static equilibrium. (Hint: Reactions at the ball-and-socket joints cannot be computed using Statics since the problem is statically indeterminant, however the tension in the cable may be found using a moment equation that gets rid of the other unknowns.)

2. Three blocks are connected by a weightless cord and rest on an inclined plane (Fig. 2(a)). The following set of simultaneous equations is derived from the free- body diagrams shown in Fig. 2(b): 100a +T + (0)R = 519.72 50a -T +R=216.55 25a + (0)T – R =108.27 Without interchanging the rows and columns, solve for the acceleration a and the tensions T and R, in the two ropes by using Gauss-Seidel iteration method. Stop all calculations after three iterations. 25 kg 50 kg 100 kg 45 1346 48 × 0,375 - 129.93 346.48 173 24 x 0.375 - 64.97 173,24 346,48 692.96 100 x 9.8 = 980 50 9,8 490 25 x 98- 245 a, acceleration 96769 T692.96 x 0.25 = 173.24 173.24

3. Draw complete, clearly labeled free-body diagrams. All unknown support reactions should be clearly labeled with a variable name.  All known values such as weight or applied forces should be clearly labeled with their known values. Don't need to show equilibrium equations, I just need free-body diagrams. Only solve this text question, not the questions in image.

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4 bar mechanism shown. Crank AB rotates counter clockwise. External force of 8.5 kN acting on link CD at Point P. Link BC makes 18 degree angle with the horizontal  A) draw free body diagrams for link AB, BC, and CD B) write the static equilibrium equations for link CD C) if force applied to link CD (link 4) as a result of contact from link BC (link 3) is 2690.52N, calculate the horizontal and vertical components of the force applied to link CD (link 4) as a result of contact from link AD (link 1) as shown

A rear suspension system for a front wheel-drive vehicle is shown here. Spring EF is offset behind member CD. The normal force due to contact between 2 wheel and the road is 4200 N. Assume the weight of the wheel and suspension system components is negligible. (a) Determine the magnitude of the force in member CD. Is the member in tension or compression? (b) Determine the support reactions at A. (c) Determine the unstretched length of the spring EF given a spring constant of 150 kN/m. 60 mm 1130 mm 60 mm 245 mm D 220 mm F 260 mm E B 165 mm 90 mm F = 4200 N