Q.3. A five-sided closed field traverse has the following angles: A=(101°03'39");B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of theEA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is notBsides are as follows: AB = 51.766m; BC= 26.947m; CD= 37.070m; DE = 35.292m;scaled.26.947 m101° 42' 09"51.766 m102° 22' 23"101° 03' 39"A19.192 m118° 55' 49"E115° 57' 40"35.292 m'DCompute the bearing of DC and azimuth of ED.Determine the linear error of closure (E) and the precision ratio.а)b)37.070 m

The value of the error and correction at any point will be same for all bearing measured from that…

Q.3. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are follows: AB = 51.766m; BC = 26.947m; CD=37.070m ; DE=35.292m; as EA =19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" A 101° 03' 39"

Q.3. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are follows: AB = 51.766m; BC = 26.947m; CD=37.070m ; DE=35.292m; as EA =19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" A 101° 03' 39"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q.2. A five-sided closed field traverse has the following angles: A= (101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" 101° 03' 39" A 19.192 m 118° 55' 49" E 115° 57' 40" 35.292 m a) Compute the bearing of CD and azimuth of DE. b) Determine the linear error of closure (E) and the precision ratio. c) Determine the balanced latitude of BC, the balanced latitude of CD and the balanced departure of DE using the compass rule. 37.070 m
Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC = 26.947m; CD=37.070m; DE = 35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. В 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" 101° 03' 39" 19.192 m 118° 55' 49" 115° 57' 40" 35.292 m 'D ts) Compute the bearing of CD and azimuth of DE. ats) Determine the linear error of closure (E) and the precision ratio. rts) Determine the balanced latitude of BC, the balanced latitude of CD and the b) c) balanced departure of DE using the compass rule. d) ints) If the coordinates of station A are (1000.000 N, 1000.000 E), compute the coordinates of “C" station. e) s) Compute the area enclosed by the traverse using the coordinate method. 37.070m
Q.3. A five-sided closed field traverse has the following angles: A = (101°0389")| B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC = 26.947m; CD =37.070m; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" A 101° 03' 39" 118° 55' 49" E 115° 57' 40" 35.292 m s) Compute the bearing of DC and azimuth of ED. Determine the linear error of closure (E) and the precision ratio. Determine the balanced latitude of DC and the balanced departure of CB c) using the compass rule. d) Points) If the coordinates of station A are (1000.000 N, 1000.000 E), compute the coordinates of "D" station. s) Compute the area enclosed by the traverse using the coordinate method. 19.192 m 37.070 m
Exercise Consider the following surveyed points presented in the figure below. The easting and northing of the point A (E=500, N=600). 1) Compute the Easting and the northing of the points B, C, D and E. 2) Compute the Azimuths GAB, and GAE. 3) Compute the deflection angle between AB and BC; and the deflection angle between CD and DE. N S63° 11' 27.32"E 1589.824 m N76° 34' 21.23"E 976.327 m B N65° 59' 59.15"E 1303.296 m N36° 07' 35.64"E 2257.235 m
Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E =(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m C 102° 22' 23" A 101° 03' 39" 118° 55' 49" E 115° 57' 40" 35.292 m d) If the coordinates of station A are (1000.000 N, 1000.000 E), compute the coordinates of “C" station. e) Compute the area enclosed by the traverse using the coordinate method. 19.192 m 37.070 m
Problem 2: In a closed traverse the measured length of the line AB is 245.08 m. If the bearing of the line is S40°35'E, the latitude of the line should be, a. – 186.130m b. +159.44 m c. – 175.64 m d. – 159.44 m e. +186.13m
4.1 A closed five-sided field traverse has the fol- lowing interior angles: A = 121°13'00"; B 136°44'30"; C = 77°05'30"; D = 94°20'30". Find the angle at E. %3D 4.2 Convert the following azimuths to bearings. а. 210°30° b. 128°22' c. 157°55' d. 300°30' e. 0°08' f. 355°10' g. 182°00' 4.3 Convert the following bearings to azimuths. a. N 20°20'E b. N 1°33' W c. S 89°28' E d. S 82°36' W e. N 89°29' E
2. Course AB of a five-sided traverse runs due north. From the balanced interior angles to the right, compute and tabulate the bearings and azimuths from north for each side of the traverses. A = 77°23'26" B = 125°58'59" C = 105°28'32" D = 116°27'02" E = 114°42'01"
In the open traverse shown below, the azimuth (from South) of AB is 310°28'. ZABC = 108°12', ZBCD = 197°10', LCDE = 278°24', ZDEF = 102°42'. Determine the bearing of BC, CD, DE, and EF. B O D F E
The length of a traverse line CD is 316.48 meters and the magnetic azimuth from the south of the line is 153054'. The departure of CD is a. + 284.21 m b. +144.05 m c. – 139.23 m d. – 284.21 m e. +139.23 m Problem 4.
6.12 See Figure 6.23. The four-sided, closed traverse has the following angles and distances: N 67°11' E B A = 51°23' АВ 713.93 ft B = 105°39' BC = 606.06 ft C = 78°11' CD = 391.27 ft D = 124°47' DA = 781.18 ft The bearing of AB is N 67°17' E. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. (d) Compute the linear error of closure and the precision ratio. FIGURE 6.23 Sketch for Problem 6.12.
14 An instrument is set-up at point M and vertical angles are observed at N (-21°15') and O (+33°45'). The height of instrument from point M is 1.5865m. The horizontal distance of NM and NO are 352.2552m and 924.5565m respectively. If point O is at elevation 621.6453m, a. Determine the elevation of N neglecting the effects of curvature and refraction. b. Determine the elevation of N making due allowance for curvature and refraction.