-1.6×10 19 x 100V =W = - APE^ KE = -11.6 x 10-d--1.6rodigin byJ(doso siq E) :19Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 μC.91 3.22pC92Ailguoid sus carsiprit esw 100-4.87 μCk1.33m101Find the electric field and potential at a point A between the two charges that is d/3 from 91.OR6.0.0ra V Girar. // in all cand botC₁ = 3.12 µF, C2 = 19.7 uF.)2.3. Find the total capacitance of the combination of capacitors shown in the figure below.

Answered: Image /qna-images/answer/56153736-9272-4c45-bf8c-de71af9455e8.jpg

Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 µC. 71 3.22pc 92 A * -4.87 PC d- 1.33m ➜ Find the electric field and potential at a point A between the two charges that is d/3 from q1.

Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 µC. 71 3.22pc 92 A * -4.87 PC d- 1.33m ➜ Find the electric field and potential at a point A between the two charges that is d/3 from q1.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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