Q.18) A series (-1)4+1 2k+1 , is: a) diverge by alternating series test c) converge by comparison test Q.19) The solution of 23x = 7 is: a) In b) converge by alternating series test d) diverge by comparison test b)logs (3) In7 3/m2 d) logs (3)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Q.18) A series
1
(-1)4+1
2k+1
, is:
a) diverge by alternating series test
c) converge by comparison test
Q.19) The solution of 2³x = 7 is:
b) converge by alternating series test
d) diverge by comparison test
b)=logs (3)
a) In
In7
3in2
d) logs (3)
+
Transcribed Image Text:Q.18) A series 1 (-1)4+1 2k+1 , is: a) diverge by alternating series test c) converge by comparison test Q.19) The solution of 2³x = 7 is: b) converge by alternating series test d) diverge by comparison test b)=logs (3) a) In In7 3in2 d) logs (3) +
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