Q.1: If 42.1 g of C4H10 0 react with 73.0 g of 02 according to the reaction Equation : C4H10 0 + 02 CO2 + H20 a) Write the balanced equation for the reaction. b) Determine the moles of given reactants b) Find the limiting reagent,

For the following unbalanced chemical equation, suppose that exactly 2.00 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of H2O is expected (assuming that the limiting reactant is completely consumed). H2 (g) + MnO2 (s) → Mn0(s) + H2 O(1) Limiting reactant: Mass of H20 = For each of the following unbalanced chemical equations, suppose that exactly 1.90 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of ICI is expected (assuming that the limiting reactant is completely consumed). I2 (s) + Cl2 (9) → ICI(9) Limiting reactant: Mass of ICl =

When nitrogen dioxide from car exhaust combines with water in the atmosphere, it forms nitric acid and nitrogen monoxide. 1) Balance the equation __NO2+ __H2O --> __HNO3 + __NO 2) When 4.50 kg of nitrogen dioxide reacts with an excess of water, how many grams of nitric acid can form?

Q.1: If 42.1 g of C4H10 0 react with 73.0 g of 02 according to the reaction Equation : C4H10 0 + 02 CO2 + H20 a) Write the balanced equation for the reaction. b) Determine the moles of given reactants b) Find the limiting reagent, c) calculate the mass of C02 formed, d) If the actual yield of CO2 is 55.8 g, what is the percent yield? Given that: C= 12 g/ mol. , O = 16 g/ mol., : H = 1 g/ mol.