Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- Can you please elaborate thisarrow_forwardVirtual Work for Beams and Frames #2 Determine the slope and the displacement at the end C of the beam. E = 200 GPa, I = 70(10°) mmª. P = Last 2 digits of ID number a = 5th digit of ID number (max value = 3) P Use %3D 4 kN ID # = 18-2363-391 P = 91 a = 6, but use 3 (max) e.g., A C |D B- a - 3 m -3 marrow_forwardThe beam supports the triangular distributed load shown below with Wmax=770 lb/ft. The reactions at A and B are vertical. 6 ft BI D 6 ft C 6 ft W B E 4.5 ft 4.5 ftarrow_forward
- A rectangular plate is acted upon by the force and couple shown. This system is to be replaced with a single equivalent force. The force acting at point B is FB = 53 N. 240 mm D 15 N The value of a is[ 400 mm FB or B C Determine the value of a if the line of action of the equivalent force is to intersect line CD 300 mm to the right of D. 15 N I understand that the Magnitude of the Equivalent Force is 53N and the line of action F' intersects line AB at 0.130m to the left of B. However, I'm having a hard time determining the value of a if the line of action of the equivalent force is to intersect line CD 300mm to right of D. Please make sure your work is clear and legible. Thx!arrow_forwardwhy you didnt included the 5*(5+5)= 50 kn in the midle ? is it nececarry to include or its against the rule please explain and if no draw again and include the 50kn in the centerarrow_forwardPlease solve with complete details. Thank you.arrow_forward
- Please answer question below and follow format providedarrow_forwardsolve very very fast in 15 min | I need a clear answer by hand, not by keyboardarrow_forwardTwo forces are applied to the construction bracket as shown. Determine the angle theta which makes the resultant of the two forces vertical. Determine the magnitude R of the resultant.arrow_forward
- Using virtual work method, for steel frame Compute Horizontal Displacement @ joint B. 6 80KN 5mm 5m A 10m 2 D I=600 x 10 mm mm BCD, A= 6000 mm AB, A= 3000mm² I=300x106 F=200 Gla. Consider Axial deformation. yarrow_forwardDetermine the magnitude of P such that the gap, 8, between the steel bar and the rigid horizontal beam just comes in contact (i.e. no force in the steel bar). In your calculations neglect the width of the steel bar. Report P in kips to two decimal places. A = PL EA + KATL rigid horizonal beam 95" 100" 60" aluminum bar E=11,000 ksi A = 1.0 in² AT=50 °F 13.5 x 100 1/°F Ɑ= 60" steel bar E= 29,000 ksi A=1.0 in² AT=75 °F a= 6.5 x 108 1/°F 80" inital gap, 8=0.157 before any temperature or load is appliedarrow_forward22:39 The beam is constructed using 2 boards and 3 rows of nails spaced equally. A shear force is applied to the board. d3 d3 Variable Values for the figure are given in the following table. Note the figure may not be to scale. d₁ d₂ d3 d4 d₁ V Value 0.2 m 0.2 m wamap.org 0.08 m 0.5 m 630 N a. Determine the Qat where the boards meet. b. Determine the moment of inertia, I. c. Determine the shear flow for each nail, q. d. Determine the shear force resisted by each nail, F. Round your final answers to 3 significant digits/figures. Q = 0.07 xm³arrow_forward
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