Q-2 Analyze the circuit. V-24V R₁-1.8 k ww R₂-2.7 k ww R₁-3.3 k R₂-8.2 k The term "Analyze the circuit" means that you need to find: Total resistance, Total Current.
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- Using the rules for parallel circuits and Ohmslaw, solve for the missing values. ETE1E2E3E4ITl1I2l33.2AI4RT3.582R116R210R3R420PTP1P2P3P4Determine the currents IR1 and IR2, (show as positive values – actual current direction). Verify in Multisim using measurement probes or digital multimeterA dc generator and a battery are connected to a resistive load RL in the figure below. For each, determine the value of RL for maximum power transfer to RL. Next is to determine RL to 75% efficiency
- In the circuit in the figure, the amplitude of the input current is 5 Amps and its phase is 0 degrees, the amplitude of the input voltage is 18 volts and its phase is 90 degrees. How many volts is the amplitude of the voltage phasor V on capacitor C1? Values of the elements in the circuit:R= 14 OhmsC1= 10j OhmsC2= -3j OhmsL= 4j OhmsWith V1, voltage peak to peak is 10 volts, R1=200 Ohm, R2=1000 Ohm and C1= 300 nF. Find Vx, voltage across the the capacitor, C1 and R2 when the frequency is 1000 Hz and 10000 HzCreate a general procedure to solve any circuit DC circuit with any number of resistors.
- Current Attempt in Progress In the figure R₁ = R₂=4.502, R3-7.202, R4 3.80, R5 1.302, and R6 R7 Rg=8.802, and the ideal batteries have emfs 1 = 26 V and 82-8.3 V. What are the (a) magnitude and (b) direction (up or down) of current is and the (c) magnitude and (d) direction of current i2? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h) battery 2? (a) Number i (b) (c) Number (d) O (e) Number i (8) O (f) Number i (h) O O R₁ R₂ www R₂ R₂ Ro Units Units Units Units ww www R₂ R₁ 4 8,0 342 R₂ O OA lead wire and an iron wire are connected in parallel. Their respective specific resistances are in the ratio 49: 24. The former carries 80 percent more current than the latter and the latter is 47 percent longer than the former. Determine the ratio of their cross sectional areas ROUND OFF TO THE NEAREST HUNDRETHSDetermine E and P3. Given R1 = 10ohms, R2 = 20ohms, R3 = 60 ohms, R4= 10ohms, R5= 20ohms, R6= 60ohms, R7= 10 ohms, R8= 20 ohms. R9= 30ohms, P6 = 540W.
- Q3/ Consider the circuit in Figure (2), answer (a)-What type of circuit is this? (b)-What is the total peak secondary voltage? (c)-Find the peak voltage across each half of the secondary. (d)-Sketch the voltage waveform across RL. 120 Vrms 4:1 00000 elile D₁ D₂2 Figure (2) WWII RL 1.0 ΚΩ150 100 + VA- a -4V AVA -7V 81. B b Figure 2 shows a simplified model of a gas-discharge lamp. One characteristic of these lamps is that they exhibit negative resistance; in other words, as current increases the voltage drops further, making such lamps inherently unstable. As such, a current-limiting ballast is required. For the connection shown in the figure: 1. Find the equivalent Thevenin circuit of the lamp. 2. Find the ballast resistance needed to limit the current drawn from a 24-volt source to 6 amperes.Help with proper measurement of current through all resistors in the parrallel cirucit below, in multisim.