Python 3.7.4: The current calendar, called the Gregorian calendar, was introduced in 1582. Every year divisible by four was created to be a leap year, with the exception of the years ending in 00 (that is, those divisible by 100) and not divisible by 400. For ­instance, the years 1600 and 2000 are leap years, but 1700, 1800, and 1900 are not. Write a program that requests a year as input and states whether it is a leap year. Below was marked incorrect for me.  I need to put it in a while loop.  Also, I'm curious if there is a way to do it without def?  Thank you! ---------------------- def leap(year):     if(year % 400 == 0):         return True     elif year % 100 == 0:         return False     elif year%4 == 0:         return True     else:         return False   def main():     year = int(input("Enter year: "))     if(leap(year)):         print(year,"is a leap year")     else:         print(year, "is not a leap year") -----------------------

Python 3.7.4:

The current calendar, called the Gregorian calendar, was introduced in 1582. Every year divisible by four was created to be a leap year, with the exception of the years ending in 00 (that is, those divisible by 100) and not divisible by 400. For ­instance, the years 1600 and 2000 are leap years, but 1700, 1800, and 1900 are not. Write a program that requests a year as input and states whether it is a leap year.

Below was marked incorrect for me.  I need to put it in a while loop.  Also, I'm curious if there is a way to do it without def?  Thank you!

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def leap(year):

    if(year % 400 == 0):

        return True

    elif year % 100 == 0:

        return False

    elif year%4 == 0:

        return True

    else:

        return False

def main():

    year = int(input("Enter year: "))

    if(leap(year)):

        print(year,"is a leap year")

    else:

        print(year, "is not a leap year")

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