College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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PW-3 An elevator motor is capable of lifting a 2,500kg elevator 50.0m with a constant speed in 12.0 seconds.
a) Apply Fet ma to find the force needed to lift the elevator.
b) Find the power of the elevator motor in watts and in horsepower. (1H.P.-750W)
c) If the power of the elevator motor is 200H.P., find the constant speed at which the 2,500kg elevator
can be raised.
d) If the power of the elevator motor is 200H.P., find the constant speed at which the elevator can be
raised if the elevator and its contents have a mass of 4,000kg
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Transcribed Image Text:PW-3 An elevator motor is capable of lifting a 2,500kg elevator 50.0m with a constant speed in 12.0 seconds. a) Apply Fet ma to find the force needed to lift the elevator. b) Find the power of the elevator motor in watts and in horsepower. (1H.P.-750W) c) If the power of the elevator motor is 200H.P., find the constant speed at which the 2,500kg elevator can be raised. d) If the power of the elevator motor is 200H.P., find the constant speed at which the elevator can be raised if the elevator and its contents have a mass of 4,000kg
Expert Solution
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Introduction:

Force, Work & Power Relation:

  • Force is defined as a push or pull capable of changing the state of rest or motion of an object. SI unit of Force is Newton (N).
  • Work done on an object is the enrgy required by an object to be raised to height h from its initial position. Mathematically, W= (Force required to raise the object) in N × (Height (h) lifted by the object) in m. SI Unit of Work is N.m or Joules (J).
  • Power is defined as work done in one second in SI unit. Unit of Power is J/s, W (Watt) or in HP.
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