Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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(See image for full explanation.) Put the following statements in order to justify the functino given equals -2/5. Basically just put the statements in a sequential order that makes sense.

Put the following statements in order to justify why
5+4n-2n²
lim
n→∞ 5n² +8n+7
Statements to choose from: Drag these statements to
the right column.
5+4n - 2n²
lim
n→∞ 5n² +8n + 7
=
lim (-2) + 4 lim
n→∞
2
5
: lim
n→∞x
−2+4.0+ 5.0
5+8.0 +7.0
lim (5) + 8 lim
n→∞
n→∞
=
n→∞ n
lim
n→∞
lim
n→∞ n
lim
n→∞
n²
n
8
1² ( 5 + ² + 7 )
n n²
5+
4
n
n
-
||
+ 7 lim
n→∞
8
2+
+ 5 lim
n→∞
2+
5
n²
7
+
n n²
2+
5+ +
n
io
5
n²
5
n²
7
n²
1
n²
1
n²
expand button
Transcribed Image Text:Put the following statements in order to justify why 5+4n-2n² lim n→∞ 5n² +8n+7 Statements to choose from: Drag these statements to the right column. 5+4n - 2n² lim n→∞ 5n² +8n + 7 = lim (-2) + 4 lim n→∞ 2 5 : lim n→∞x −2+4.0+ 5.0 5+8.0 +7.0 lim (5) + 8 lim n→∞ n→∞ = n→∞ n lim n→∞ lim n→∞ n lim n→∞ n² n 8 1² ( 5 + ² + 7 ) n n² 5+ 4 n n - || + 7 lim n→∞ 8 2+ + 5 lim n→∞ 2+ 5 n² 7 + n n² 2+ 5+ + n io 5 n² 5 n² 7 n² 1 n² 1 n²
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