public static void BubbleSort(int A(]) { for (int i = 0; i < A.length; i++) { for (int j = 0; j < A.length; j++) { if (A[j] > A[j+l]) { //£ill in here

(java) q6

(Java) In which of these cases would it be good to use an enum ?   Group of answer choices   1. You want a variable where there is flexibility to allow users to input an arbitrary string containing only a single word (i.e. no spaces). 2. You need to have a variable that encodes which day of the week it is. 3. You need to have a variable for a person’s birthday. 4. You need to output all possible integers between 1 and n, where n is input by the user.

(Intro to Java) 3. pls help

(JAVA)A set of if statements can do the same job as a switchstatement. What is a good reason to choose one over the other?   Group of answer choices   1. Choose a switch statement when you have more than two cases for a single variable. If your conditions depend on the interaction between multiple variables use if statements.    2. All options are correct.   3. Proper coding conventions suggest that using if statements is preferable.   4. Choosing a switch statement when your conditions involve integers, and if statements if your conditions involve doubles.    5. Proper coding conventions suggest that if statements are leftover from older programming languages, and modern code should use switch statements.

(Intro to Java)

1. (JAVA)Determine the output of the following code. You must show the values of the variables as you iterate through the loop for full credit. int value = 3; int limit = 9; int result = 0;        for(int x=0;  x<limit;  x++) {                   result = result + value; }        System.out.println( result);

(JAVA CODE) write an integer method that will calculate the sum of integers within a given range using a loop. sumBet (1, 10): 55 while / for public static int sumBet (int n1, int n2) { int sum = 0; int i = n1; while (i < n2+1) { sum = sum + i; i++; } return sum; } public static int sumBet (int n1, int n2) { int sum = 0; for (int i = n1; i < n2+1; i++) sum = sum + i; return sum; }