public static int countLeaves (BinaryTree tree) Returns the number of leaf nodes in the tree. public static int countNonLeaves (BinaryTree tree) Returns the number of non-leaf nodes in the tree. public static int getHeight (BinaryTree tree) Returns the height of the tree. public static void print PreOrder (BinaryTree tree)

2-3-4 Trees Java Programming Given the following sequence of numbers:   4.0 5.0 6.0 1.0 2.0 3.0 2.5 3.5 7.0 3.9 8.0 3.8 6.5 6.7 9.0   Show what the 2-3-4 tree looks like after each insert. This means you start with a blank tree and then show the 2-3-4 tree after inserting 4.0. Then, from that 2-3-4 tree, show what it looks like after you insert 5.0 into it. Repeat for the remaining numbers. There are 15 numbers to insert so you should be showing 15 trees progressively being built. Assume we are maintaining numbers in ascending order correctly within the tree as discussed in the slides. From the tree you have from completing question 1, which of the following is true (remember that more than one answer may apply) There are 6 leaf nodes in the tree No matter what the next number is to insert, there will definitely be a node that will be split Each non-leaf node in the final tree has exactly 2 children None of the above Finally, which of the following concepts about a 2-3-4 tree are…

Java - The node (80, 85, 90) is split. Enter each node's keys after the split, or "none" if the node doesn't exist.

the Java code that removes the top BinaryTree of a tree andreturns the root of the resulting tree

Please, help. I'm working with notebook python. class Tree:    """A rooted binary tree"""    def __init__(self):        self.root = None        self.left = None        self.right = None def is_empty(tree: Tree) -> bool:        """Return True if and only if tree is empty."""        return tree.root == tree.left == tree.right == None def join(item: object, left: Tree, right: Tree) -> Tree:    """Return a tree with the given root and subtrees."""    tree = Tree()    tree.root = item    tree.left = left    tree.right = right    return tree   The following code builds a binary tree, MORSE, which implements the upper-case Morse code, as per the image below. More information on Morse code can be found on Wikipedia. You will need to run this code block to use in your solutions. In [33]:   EMPTY = Tree()

please, can you help me, I'm working with notebooks python. class Tree:    """A rooted binary tree"""    def __init__(self):        self.root = None        self.left = None        self.right = None def is_empty(tree: Tree) -> bool:        """Return True if and only if tree is empty."""        return tree.root == tree.left == tree.right == None def join(item: object, left: Tree, right: Tree) -> Tree:    """Return a tree with the given root and subtrees."""    tree = Tree()    tree.root = item    tree.left = left    tree.right = right    return tree The following code builds a binary tree, MORSE, which implements the upper-case Morse code, as per the image below. More information on Morse code can be found on Wikipedia. You will need to run this code block to use in your solutions. EMPTY = Tree()H = join('H',EMPTY,EMPTY)V = join('V',EMPTY,EMPTY)F = join('F',EMPTY,EMPTY)L = join('L',EMPTY,EMPTY)P = join('P',EMPTY,EMPTY)J = join('J',EMPTY,EMPTY)B = join('B',EMPTY,EMPTY)X =…

Java / Trees: Which node in a tree does not have a parent? Multiple chocie. center null root leaf

True or False: Any node in a tree can be viewed as being the root of its own tree.

Use Java to create a Binary Search Tree Class with the following Operations: Insert(int n) : add a node the tree with value n. Its O(lgn) Find(int n) : find a node the tree with value n. Its O(lgn) Delete (int n) : delete a node the tree with value n. Its O(lgn) Display(): prints the entire tree in increasing order. O(n).

Create the corresponding counting trees with the following traversals:1. Pre: IAMHEDBCFLPost: EHDMALFCBIIn: AHEMDICFLB2. Pre: ABDGCEHIFIn: DGBAHEICF3. Post: CBFEGDAIn: CBAEFDG4. Post: FABG/+CD - ^*In: F/AGB*+^C-D