Provide an explanation for the straight curvature of an LCD computer monitor's display.

Hi, I have the answer for this question but I'm not sure how it was done. I worked it out on paper and ended up with 1.3 x 10^1  Could you please explain in as much detail each step to get to the answer becasue I'm confused about where I went wrong since I was able to get everything except for the correct power.

5. Given: Three forces act on particle P. Force A has a magnitude of 15 N and acts 60° CCW from the positive x-axis. Force B has a magnitude of 60 N and acts along a ray from point P with a slope of -4/3. Force C has a magnitude of 10 N and acts straight left (180° CCW from positive x- axis). Find the Vector Sum: a. Draw a neat, labeled, scaled diagram representing the tip-to-tail vector addition R=A+B+C. Rx = 15cos60+60(3/5) — 10 and Ry = 15sin60-60(4/5) b. Add the three vectors to find the scalar components of the resultant, Rx and Ry. C. Find the magnitude of the resultant R and the angle 0 it makes with the positive x-axis.

There are two forces on the 2.71kg box in the overhead viewof the figure but only one is shown. For F - 243N.o- 122ms. and - 33.0 find the second force la) in unit-vector notation and as (b) a magnitude and (c) a direction. IState the direction as anegative angle measured from the x direction) la) Number i Units (b) Number Units k) Number Units