Provide a structure for the given compound. molecular mass 71; IR: 3200 (strong, broad), 2250 cml; no absorptions in the 1500–2250 cm range; 'H NMR: 8 2.62 (2H, t, J = 6 Hz), 8 3.42 (1H, broad s; eliminated by D,O shake), ô 3.85 (2H, t, J = 6 Hz).

Provide a structure for the given compound. molecular mass 71; IR: 3200 (strong, broad), 2250 cml; no absorptions in the 1500–2250 cm range; 'H NMR: 8 2.62 (2H, t, J = 6 Hz), 8 3.42 (1H, broad s; eliminated by D,O shake), ô 3.85 (2H, t, J = 6 Hz).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

Provide a structure for the given compound.
molecular mass 71;
IR: 3200 (strong, broad), 2250 cm¯1; no absorptions in the 1500–2250 cm¯ range;
'H NMR: 8 2.62 (2H, t, J = 6 Hz), 8 3.42 (1H, broad s; eliminated by D, O shake), 8 3.85 (2H, t, J = 6 Hz).
Deduce the structure of the compound and draw hydrogens on oxygen or nitrogen where needed.
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