Prove the part of the theorem which lets w be any solution of Ax=b, and defines v₁=w-p. Show that Vh is a solution of Ax=0. This shows that every solution of Ax=b has the form w=p+Vh, with p a particular solution of Ax=b and V₁ a solution of Ax = 0. Let w and p be solutions of Ax= b. Substitute for v₁ from the equation w=p+Vn. Avh=A( What theorem should be used next? A. Ax=x₁a₁ + X₂ª₂ + ... +Xnan OB. u+v=v+u C. A(cu) = c(Au) D. A(u + v) = Au + Av Use that theorem to change the right side of the equation found above. Av₁ = Simplify the right side of the equation that was just found. Av₁ = So Av₁ = Thus, vis a solution of Ax = 0.

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