Prove that 3n+ 7 is even if and only if n is odd. You must use definitions of even (and odd, if needed). Do not use "even plus even is even" or similar rules of thumb.

i do not undertstand where the 8 has come from in q2c

Answer True or False

Click and drag the steps in the correct order to show that if n is a positive integer, then n is even if and only if 7n +4 is even. Suppose that n is even. Suppose that n is not even. Thus, 7n + 4 = 14k +10= 2(7k+5). Then, 7n + 4 = 14k + 2 = 2(7k + 1). Since n is even, it can be written as 2k for some integer k. This is 2 times an integer; so it is even as desired. Then, n can be written as 2k +1 for some integer k. Thus, 7n + 4 = 14k +11 = 2(7k+5)+1. Then, 7n + 4 = 14k + 4 = 2(7k+ 2). This is 1 more than 2 times an integer, so it is odd. Reset

can the answer be 2tan X if  diff of 6 and 3 that is whole number

Write the set of integers that is greater than -3 but less than or equal to 5 using both notations.

Please explain and double check your answer

answer was not right, please help and explain. thanks

) biven that (5A) -3-17 find A 52