Propose a structure for the compound with the formula C5H11Cl that would produce the following C13 NMR spectrum.

A molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm1. Provide the structures of the starting material (1 pt) and product (2 pts) NaOH H20 C5H1,Br 6H triplet 4H quintet 1H quintet 10 8 7 6. 4 3 1 HSP-06-347 ppm

Below is the ¹H NMR spectrum of a constitutional (structural) isomer of C9H100, with the integration given above each peak. In addition to other peaks not given here, the IR spectrum of the isomer showed a strong peak at 1700 cm-1 Determine which of the structures given below the spectrum matches the 1H NMR spectrum. H3C 5 A C CH3 CH3 HO B D PPM CH3 CH ₂ 2 FM N 3

Use the NMR tables & to predict the range (ppm) where each compound should absorb.

Predict the theoretical number of different NMR signals produced by each compound,and give approximate chemical shifts. Point out any diastereotopic relationships.(a) 2-bromobutane