PROGRAM FOR LoNGEST COMMON SUBSEQUECE B/W 2 STRINGS Input: output: abcdda, bdda. LENGTH OF SUBSEQUENCE
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- Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…Write Context Free Grammers for: All strings having even a’s and odd b’s All strings that start and end with different letters anbn anbmandef while_loops(string1: str, string2: str) -> str:""" Given two strings <string1> and <string2>, return a new string that contains letters from these two strings "interwoven" together, starting with the first character of <string1>. If the two strings are not of equal length, then start looping "backward-and-forwards" in the shorter string until you come to the end of the longer string.we ask that you used while loops and keep them simple and precise.>>> while_loops("abcde","12")'a1b2c1d2e1'>>> while_loops("ab","123")'a1b2a3'>>> while_loops("abcdfe","123")'a1b2c3d2f1e2'>>> while_loops("c","ab")'cacb'""" prove these doctests and write the code in python and don't add any import or any dictionaries or dictionary methods or any try-except statements
- def while_loops(string1: str, string2: str) -> str:""" Given two strings <string1> and <string2>, return a new string that contains letters from these two strings "interwoven" together, starting with the first character of <string1>. If the two strings are not of equal length, then start looping "backward-and-forwards" in the shorter string until you come to the end of the longer string. We ask that you use while loops and keep them simple and precise.>>> while_loops("abcde","12")'a1b2c1d2e1'>>> while_loops("ab","123")'a1b2a3'>>> while_loops("abcdfe","123")'a1b2c3d2f1e2'>>> while_loops("c","ab")'cacb'""" don't use any reverse or any other def do in on def while_loop, prove these doctests and write the code in python and don't add any import or any dictionaries or dictionary methods or any try-except statementsIn c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards. End each loop with a newline. Ex: If courseGrades (7, 9, 11, 10), print: - 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]) See How to Use zyBooks" Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i-8; 1 NUM VALS; ++) { cin>> courseGrades[1]; } Your solution goes…Given a string s passed by reference, write a C++ function that return the firstnon-repeating character in it and return its index. If it does not exist, return -1. int firstUniqChar(string s)Sample Output:Input: s = "leetcode"Output: 0
- caleulator Create four-function. 4. f using fallowing for fractions by foomu20s Addilion: alb + cld = (a'd + b'c)/(6'd). %3D Subtraction: a/b - cld = (a*d- b'c) |(b"d). Multiplication: a|b* c/d = (a*c) / (b"c) %3D %3D • The m should display above mentioned formulas first. The should take the values of user from should then display user. The the piogram desult of each process Addition, subtraction Multiplication and Division. lines separate an on Screen.Q. WAP to reverse string in Java by using while loop without reverse function.Write a C++ program using for loop to print all the different arrangements of theletters A, B, C, D and E. Each string printed is a permutation of ABCDE (it means all strings will bedifferent from each other). donot use arrays