Please help with questions 1,2,4 SolutionsProcedure:1. Prepare 50 mL of a 0.100 M solution of LiCl.2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations:0.0500 M, 0.0250 M, 0.0125 M, and0.00625 M. The dilutions should leave ~30 mL of the 0.100 Mstock solution to finish the series.(Note that each solution in the series is ½ the concentration of the previous solution.)3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel(or other plotting software) and apply a linear regression analysis to the plot.4. Repeat steps 1-3 for formic acid.LICIFormic Acidms cm10.66mol/L0.10000ms cm1.791.60mol/L0.100007.750.050000.050006.300.025001.500.025005.570.012501.450.012505.210.006251.430.00625Questions:1. Determine the mass of LİCI (42.394 g/mol) required for Step l.2. Show your calculations for the volume of 0.100 M LİCI required for each dilution in Step 2.(HINT: dilution law: M¡Vi = M¿V2)3. Submit your two clearly labeled plots (including their linear fits) from Excel (or other plottingsoftware). There is a short video on D2L on how to plot using Excel.4. Which compound is the stronger electrolyte? What do you believe to be the major factor accounting forthe difference?

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Procedure: 1. Prepare 50 mL of a 0.100 M solution of LiCl, 2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations: 0.0500 M, 0.0250 M., 0.0125 M., and 0.00625 M. The dilutions should leave-30 mL of the 0.100 M stock solution to finish the series. (Note that each solution in the series is ½ the concentration of the previous solution.) 3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel (or other plotting software) and apply a linear regression analysis to the plot. 4. Repeat steps 1-3 for formic acid. LICI mS cm' 10.66 Formic Acid mol/L mol/L 0.10000 0.05000 ms cm 1.79 1.60 0.10000 7.75 0.05000 6.30 0.02500 1.50 0.02500 5.57 0.01250 1.45 0.01250 5.21 0.00625 1.43 0.00625 Questions: 1. Determine the mass of LiCI (42.394 g/mol) required for Step 1.

Procedure: 1. Prepare 50 mL of a 0.100 M solution of LiCl, 2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations: 0.0500 M, 0.0250 M., 0.0125 M., and 0.00625 M. The dilutions should leave-30 mL of the 0.100 M stock solution to finish the series. (Note that each solution in the series is ½ the concentration of the previous solution.) 3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel (or other plotting software) and apply a linear regression analysis to the plot. 4. Repeat steps 1-3 for formic acid. LICI mS cm' 10.66 Formic Acid mol/L mol/L 0.10000 0.05000 ms cm 1.79 1.60 0.10000 7.75 0.05000 6.30 0.02500 1.50 0.02500 5.57 0.01250 1.45 0.01250 5.21 0.00625 1.43 0.00625 Questions: 1. Determine the mass of LiCI (42.394 g/mol) required for Step 1.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.16QAP

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