Help! ## Hypothesis Testing for Pre-Test and Post-Test Scores### Problem StatementYou wish to test the following claim ($H_a$) at a significance level of $\alpha = 0.01$. For the context of this problem, the first data set represents a pre-test and the second data set represents a post-test. You'll have to be careful about the direction in which you subtract.- **Null Hypothesis ($H_0$)**: $\mu_d = 0$- **Alternative Hypothesis ($H_a$)**: $\mu_d > 0$### Background InformationYou believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for $n = 46$ subjects. The average difference (post - pre) is $\overline{d} = 6.2$ with a standard deviation of the differences of $s_d = 35.3$.### Questions to Answer1. **Test Statistic Calculation** - **What is the test statistic for this sample?** Calculate and round to 4 decimal places. \[ \text{test statistic} = \boxed{} \]2. **P-Value Determination** - **What is the p-value for this sample?** Round to 4 decimal places. \[ \text{p-value} = \boxed{} \]3. **P-Value Comparison** - **The p-value is:** - $\mathbf{o}$ less than (or equal to) $\alpha$ - $\mathbf{o}$ greater than $\alpha$4. **Null Hypothesis Decision** - **This test statistic leads to a decision to:** - $\mathbf{o}$ reject the null - $\mathbf{o}$ accept the null - $\mathbf{o}$ fail to reject the null5. **Final Conclusion** - **As such, the final conclusion is that...**### Explanation of Terms and Calculations- **Test Statistic**: This is a standardized value derived from sample data during a hypothesis test. It is calculated using the formula for t-test statistics based on sample means and standard deviations.- **P-Value**: The probability that the observed results would occur if

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Description: Help! ## Hypothesis Testing for Pre-Test and Post-Test Scores### Problem StatementYou wish to test the following claim ($H_a$) at a significance level of $\alpha = 0.01$. For the context of this problem, the first data set represents a pre-test a

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problem, the first data set represents a pre-test and the second data set represents a post-test. You'll have to be careful about the direction in which you subtract. 0 = Prl :°H 0 < Prl : ®H You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for n = 46 subjects. The average difference (post - pre) is d = 6.2 with a standard deviation of the differences of sa = 35.3. a. What is the test statistic for this sample? test statistic = Round to 4 decimal places. b. What is the p-value for this sample? Round to 4 decimal places. p-value = c. The p-value is... O less than (or equal to) a greater than a d. This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null e. As such, the final conclusion is that...

problem, the first data set represents a pre-test and the second data set represents a post-test. You'll have to be careful about the direction in which you subtract. 0 = Prl :°H 0 < Prl : ®H You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for n = 46 subjects. The average difference (post - pre) is d = 6.2 with a standard deviation of the differences of sa = 35.3. a. What is the test statistic for this sample? test statistic = Round to 4 decimal places. b. What is the p-value for this sample? Round to 4 decimal places. p-value = c. The p-value is... O less than (or equal to) a greater than a d. This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null e. As such, the final conclusion is that...

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Help!

## Hypothesis Testing for Pre-Test and Post-Test Scores

### Problem Statement
You wish to test the following claim ($H_a$) at a significance level of $\alpha = 0.01$. For the context of this problem, the first data set represents a pre-test and the second data set represents a post-test. You'll have to be careful about the direction in which you subtract.

- **Null Hypothesis ($H_0$)**: $\mu_d = 0$
- **Alternative Hypothesis ($H_a$)**: $\mu_d > 0$

### Background Information
You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for $n = 46$ subjects. The average difference (post - pre) is $\overline{d} = 6.2$ with a standard deviation of the differences of $s_d = 35.3$.

### Questions to Answer

1. **Test Statistic Calculation**
- **What is the test statistic for this sample?**
Calculate and round to 4 decimal places.

\[
\text{test statistic} = \boxed{}
\]

2. **P-Value Determination**
- **What is the p-value for this sample?** Round to 4 decimal places.

\[
\text{p-value} = \boxed{}
\]

3. **P-Value Comparison**
- **The p-value is:**
- $\mathbf{o}$ less than (or equal to) $\alpha$
- $\mathbf{o}$ greater than $\alpha$

4. **Null Hypothesis Decision**
- **This test statistic leads to a decision to:**
- $\mathbf{o}$ reject the null
- $\mathbf{o}$ accept the null
- $\mathbf{o}$ fail to reject the null

5. **Final Conclusion**
- **As such, the final conclusion is that...**

### Explanation of Terms and Calculations
- **Test Statistic**: This is a standardized value derived from sample data during a hypothesis test. It is calculated using the formula for t-test statistics based on sample means and standard deviations.
- **P-Value**: The probability that the observed results would occur if

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Can I also get assistance with d
Part (iv) of the question please
d and e please!
assess2/?cid%3D78918&aid%3D5632695#/skip/11 a Project-A.. The table below sows the number of hate crimes for 2007 to 2018. The value for 2007 is slightly different than the actual value so that each student gets their own unique problem. Number of hate Year crimes 2007 7612 2008 7783 2009 6604 2010 6628 2011 6222 2012 5796 2013 5928 2014 5479 2015 5850 2016 6121 2017 7175 2018 7120
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