Problem Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose drag force is expressed as Fdrag = kmv where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo Solution: The net force along the x-axis is: EF = -F then: mv = m Since acceleration is the first time derivative of velocity a = dv/dt, mv = m We can eliminate time dt by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression = -k "Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following: = vo which shows that velocity decreases in a linear manner.
Problem Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose drag force is expressed as Fdrag = kmv where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo Solution: The net force along the x-axis is: EF = -F then: mv = m Since acceleration is the first time derivative of velocity a = dv/dt, mv = m We can eliminate time dt by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression = -k "Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following: = vo which shows that velocity decreases in a linear manner.
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![QUESTION 4
Problem
Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any
point x in a fluid whose drag force is expressed as
Fdrag = kmv
where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo.
Solution:
The net force along the x-axis is:
ΣΕ-F
= m
then:
mv = m
Since acceleration is the first time derivative of velocity a = dv/dt,
mv = m
We can eliminate time dt by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression
= -k
"Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following:
= Vo-
which shows that velocity decreases in a linear manner.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d0e069a-0ec8-47e3-857b-c2ed493ee992%2F54d1b11d-9ce7-43e5-af4d-c996f75df2b2%2Fvhxjk2w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 4
Problem
Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any
point x in a fluid whose drag force is expressed as
Fdrag = kmv
where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo.
Solution:
The net force along the x-axis is:
ΣΕ-F
= m
then:
mv = m
Since acceleration is the first time derivative of velocity a = dv/dt,
mv = m
We can eliminate time dt by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression
= -k
"Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following:
= Vo-
which shows that velocity decreases in a linear manner.
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