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Problem II. The fabricated steel members are being assembled into a truss on-site in the municipality of Alfonso, Cavite. The assembly started at the elevated ground at both sides and is to meet at the midspan. Nearing to the end of construction, it was found that the last member, CD, was fabricated too short by A mm (see the given table in MS afe teams). The engineer then came up with an idea of applying a force P at joints C and D as shown to close the gap. P. 3 m E -3 m- - 3 m- -3 m- Use E = 200 GPa and cross-sectional area of members BC, DE, CD cach 4500 mm² while AC and DF being 6363.961 mm? a) Determine the necessary force, P, to close the gap in kN. b) If force P will then be removed after being assembled, calculate the force in CD in kN.

Problem II. The fabricated steel members are being assembled into a truss on-site in the municipality of Alfonso, Cavite. The assembly started at the elevated ground at both sides and is to meet at the midspan. Nearing to the end of construction, it was found that the last member, CD, was fabricated too short by A mm (see the given table in MS afe teams). The engineer then came up with an idea of applying a force P at joints C and D as shown to close the gap. P. 3 m E -3 m- - 3 m- -3 m- Use E = 200 GPa and cross-sectional area of members BC, DE, CD cach 4500 mm² while AC and DF being 6363.961 mm? a) Determine the necessary force, P, to close the gap in kN. b) If force P will then be removed after being assembled, calculate the force in CD in kN.

Materials Science And Engineering Properties
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter8: Engineering Materials
Section: Chapter Questions
Problem 85CQ
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Problem II. The fabricated steel members are being assembled into a truss on-site in the municipality of Alfonso, Cavite. The assembly started at the elevated ground at both sides and is to meet at the midspan. Nearing to the end of construction, it was found that the last member, CD, was fabricated too short by A mm (see the given table in MS teams). The engineer then came up with an idea of applying a force P at joints C and D as shown to close the gap. P. ' 3 m B E -3 m -3 m- -3 m- Use E = 200 GPa and cross-sectional area of members BC, DE, CD each 4500 mm² while AC and DF being 6363.961 mm? a) Determine the necessary force, P, to close the gap in kN. b) If force P will then be removed after being assembled, calculate the force in CD in kN.
Transcribed Image Text:Problem II. The fabricated steel members are being assembled into a truss on-site in the municipality of Alfonso, Cavite. The assembly started at the elevated ground at both sides and is to meet at the midspan. Nearing to the end of construction, it was found that the last member, CD, was fabricated too short by A mm (see the given table in MS teams). The engineer then came up with an idea of applying a force P at joints C and D as shown to close the gap. P. ' 3 m B E -3 m -3 m- -3 m- Use E = 200 GPa and cross-sectional area of members BC, DE, CD each 4500 mm² while AC and DF being 6363.961 mm? a) Determine the necessary force, P, to close the gap in kN. b) If force P will then be removed after being assembled, calculate the force in CD in kN.
Prob 2 (A in mm) 6.300
Transcribed Image Text:Prob 2 (A in mm) 6.300
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