Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K=(1/2)mv2, K2-(1/2)mv2 But it was mentioned that: so, K2 in terms of v, is K2=( mv², Substituting the expression for K, results to K2= )K1 Since work done is W=AK=K -K Evaluating results to W-(

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Chapter1: Units, Trigonometry. And Vectors
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Problem
A moving electron has a Kinetic Energy Kg. After a net amount of work is done on it, the electron is moving one-quarter
as fast in the opposite direction. What is the work done W in terms of K4?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
Kq=(1/2)mv2,
K2-(1/2)mv2
But it was mentioned that:
so, K2 in terms of v, is
K2=(
mv²,
Substituting the expression for K, results to
K2=(
)K1
Since work done is
W=AK=K
-K
Evaluating results to
W-(
Transcribed Image Text:Problem A moving electron has a Kinetic Energy Kg. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that Kq=(1/2)mv2, K2-(1/2)mv2 But it was mentioned that: so, K2 in terms of v, is K2=( mv², Substituting the expression for K, results to K2=( )K1 Since work done is W=AK=K -K Evaluating results to W-(
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