PROBLEM: A dry soil is mixed with 17% by mass with water and compacted. The volume of wet soil is 0.001 m³ and has a mass of 1.6 kg. If the specific gravity of soil is 2.70. a.What is the dry unit weight of the soil sample in kN/m3? b.What is the void ratio of the sample? c.What is the degree of saturation of the sample, in percent?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Answer the following question, show the solution step by step and finalize your final answer by a 4 significant figure. and Box the final answer with the unit don't forget. Thank you for helping me. 

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PROBLEM:
A dry soil is mixed with 17% by mass with water and compacted.
The volume of wet soil is 0.001 m³ and has a mass of 1.6 kg. If the
specific gravity of soil is 2.70.
a.What is the dry unit weight of the soil sample in kN/m3?
b.What is the void ratio of the sample?
c.What is the degree of saturation of the sample, in percent?
Transcribed Image Text:PROBLEM: A dry soil is mixed with 17% by mass with water and compacted. The volume of wet soil is 0.001 m³ and has a mass of 1.6 kg. If the specific gravity of soil is 2.70. a.What is the dry unit weight of the soil sample in kN/m3? b.What is the void ratio of the sample? c.What is the degree of saturation of the sample, in percent?
EXAMPLE #2:
A fully saturated clay sample has a mass of 1526 grams. After oven drying, its mass was reduced to 1053 grams.
The specific gravity soil particles is 2.7.
a. What is the moisture content of the sample in percent?
b. What is the void ratio?
c. What is the porosity?
Given:
mSAT = 1526 g
MDRY = 1053 g
G = 2.7
S= 1
1. Moisture content, MC
2. Void ratio, e
3. Porosity, n
original – dry
dry
Gx MC = Sx e
MC
1+e
1526 - 1053
(2.7)(44.9193%) = (1)(e)
1.2128
MC
x 100%
1053
1+1.2128
MC = 44. 9193%
e = 1.2128
n = 0.5481
Transcribed Image Text:EXAMPLE #2: A fully saturated clay sample has a mass of 1526 grams. After oven drying, its mass was reduced to 1053 grams. The specific gravity soil particles is 2.7. a. What is the moisture content of the sample in percent? b. What is the void ratio? c. What is the porosity? Given: mSAT = 1526 g MDRY = 1053 g G = 2.7 S= 1 1. Moisture content, MC 2. Void ratio, e 3. Porosity, n original – dry dry Gx MC = Sx e MC 1+e 1526 - 1053 (2.7)(44.9193%) = (1)(e) 1.2128 MC x 100% 1053 1+1.2128 MC = 44. 9193% e = 1.2128 n = 0.5481
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