College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:Problem 9: (10% of Assignment Value)
A gymnast with a mass of 59.4 kg jumps on a trampoline.
What force, in newtons, must the trampoline apply to achieve a directly upward acceleration of 7.21 m/s² .?
F = ||
N
sin()
cos()
tan()
Π
(7
8
9
HOME
cotan()
asin()
acos()
E
^^^
4 5
6
atan() acotan()
sinh()
*
1
2
3
←
cosh()
tanh()
Degrees Radians
cotanh()
+
-
0
END
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Transcribed Image Text:Problem 9: (10% of Assignment Value)
A gymnast with a mass of 59.4 kg jumps on a trampoline.
What force, in newtons, must the trampoline apply to achieve a directly upward acceleration of 7.21 m/s² .?
F = ||
N
sin()
cos()
tan()
Π
(7
8
9
HOME
cotan()
asin()
acos()
E
^^^
4 5
6
atan() acotan()
sinh()
*
1
2
3
←
cosh()
tanh()
Degrees Radians
cotanh()
+
-
0
END
VO BACKSPACE
DEL CLEAR
Submit
Hint
10 Submission(s) Remaining
Feedback
I give up!
Hints: 1% deduction per hint. Hints remaining:
Submission History
Feedback: 1% deduction per feedback.
All Date times are displayed in Eastern Standard Time Red submission date times indicate late work.
Date
Time
Answer
Hints
Feedback
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- A body of mass m is attracted toward a 11.1 kg mass, 31.5 cm away, with a force of magnitude 6.60 10-8 N. Find m. can you also add the units!arrow_forward1. Multiplication or division: keep the same number of significant figures in the product or quotient as is in the least precise factor. Examples: 3.1 * 25.6=79.360000... = 79 6.7/981.0=0.0068297655... = 0.0068 keep only 2 significant digits 2. Powers or roots: keep the same number of significant figures as in the original number. Example: Sqrt(38) 6.164414... keep only 2 significant digits = 6.2 (11.6)² = 134.5600000... = 135 Exercises 3. Addition or subtraction: Round off, to the number of decimal places determined by the number with the least number of places beyond the decimal point. Example: 31.5+24.61 +3.28+1.19 +0.762 +0.003 = 61.345 1. 3.9 * 78.9= = 61.3 (correct result) 2. 32.01 +96.321 +36.98 +0.00023 +28.9= 3. 26.9/98 = 4. 421 0.003 =arrow_forwardA girl weighing 45kg is standing on the floor, exerting a downward force of 200N on the floor. The force exerted on her by the floor isarrow_forward
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- Problem 4: Starting from the origin at time t = 0, a particle is given an initial velocity vo along the +x axis. The particle's motion can be described by v(x) = vo(1kx)¹/3 where k is a positive constant. (a) Determine the retarding force F(v) as a function of velocity. [Note: Don't write your final answer in the form F(x, v)! You know v(r), so make sure your expression contains no explicit dependence on z.] (b) Determine x(t), the position of the particle as a function of time. (c) Find the time and place where the particle comes instantaneously to rest, tƒ and xƒ. For each part, check your result for dimensional consistency and limiting-case behavior.arrow_forwardHelparrow_forwardConsider an object of mass 78.3kg. Assume that it’s made up of equal numbers of protons, neutrons, and electrons. Youve separated the boxes of protons and electrons by a distance of 65 m. If you were to release the clump of protons from their box, how much acceleration would the clump of protons undergo due to its attraction to the clump of electrons in the other box?arrow_forward
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