
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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![Problem 6 Let op: VV be a linear map (also called "self-map" or endomorphism) of a
vector space V. Given any real polynomial Pag+a+a2x²++ add, we can define
the linear map P(): VV as aqldy +14+244 +...+ad popo...oy.
d-times
For any ≥0, we will denote pop0...04 = 4° (400 = Idy and 4°1 = 4).
(-times
As a reminder: for any polynomials P,Q € R[x], Q(p) P(4)
P() Q() and (P+Q)() = P(x)+Q(4).
=
(QP)(x) = (PQ)(4) =
(1) Given a polynomial P, show that for any E Ker(P()), () Є Ker(P()).
hint: for a vector w being in the kernel of a linear map just means (w)=0+ try to
show that and P(p) commute.
So induces a linear self-map of the vector subspace Ker(P()).
(2) Let ab be real numbers, we recall that 2- (a+b)x+ab = (-a)(x - b). We
want to prove that
Ker(p2
(a) Simplify
(a+b)+ abldy) = Ker(-ald) Ker( - bld)
((-a) - (x - b)).
(b) Apply the equality of polynomials obtained in the previous question to p.
(c) Show that if Ker(2-(a+b)+abldy), then (-ald)(v) € Ker(p-bldy).
hint: meaning of being in the kernel of a linear map? + use that polynomial multi-
plication corresponds to composition, when applied to a linear map
(d) Show that if Є Ker(p2-(a+b)+abldy), then (p-bld)(v) € Ker(p-aldy).
(e) Now prove that Ker(2- (a + b) + abldy) = Ker(y-ald) + Ker( - bld).
hint: double inclusion as usual. One inclusion uses (2) (b) and for the other, one can
use the fact that if U, W, H are vector subspaces of V and UC H and WCH; then
as H is closed under addition U+WCH.](https://content.bartleby.com/qna-images/question/20d8f953-c934-452a-953c-857d66901886/2cc55217-e372-4886-aaef-986f81598818/j9zxpos_thumbnail.jpeg)
Transcribed Image Text:Problem 6 Let op: VV be a linear map (also called "self-map" or endomorphism) of a
vector space V. Given any real polynomial Pag+a+a2x²++ add, we can define
the linear map P(): VV as aqldy +14+244 +...+ad popo...oy.
d-times
For any ≥0, we will denote pop0...04 = 4° (400 = Idy and 4°1 = 4).
(-times
As a reminder: for any polynomials P,Q € R[x], Q(p) P(4)
P() Q() and (P+Q)() = P(x)+Q(4).
=
(QP)(x) = (PQ)(4) =
(1) Given a polynomial P, show that for any E Ker(P()), () Є Ker(P()).
hint: for a vector w being in the kernel of a linear map just means (w)=0+ try to
show that and P(p) commute.
So induces a linear self-map of the vector subspace Ker(P()).
(2) Let ab be real numbers, we recall that 2- (a+b)x+ab = (-a)(x - b). We
want to prove that
Ker(p2
(a) Simplify
(a+b)+ abldy) = Ker(-ald) Ker( - bld)
((-a) - (x - b)).
(b) Apply the equality of polynomials obtained in the previous question to p.
(c) Show that if Ker(2-(a+b)+abldy), then (-ald)(v) € Ker(p-bldy).
hint: meaning of being in the kernel of a linear map? + use that polynomial multi-
plication corresponds to composition, when applied to a linear map
(d) Show that if Є Ker(p2-(a+b)+abldy), then (p-bld)(v) € Ker(p-aldy).
(e) Now prove that Ker(2- (a + b) + abldy) = Ker(y-ald) + Ker( - bld).
hint: double inclusion as usual. One inclusion uses (2) (b) and for the other, one can
use the fact that if U, W, H are vector subspaces of V and UC H and WCH; then
as H is closed under addition U+WCH.
SAVE
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