Problem 5: (a) For a driven, damped harmonic oscillator, the peak of the amplitude (and therefore the maximum potential energy) occurs for a driving frequency of w = ₂ = √w – 2/3². Determine the driving frequency at which the kinetic energy of the system is a maximum. (b) Make a "resonance peak" plot of kinetic energy versus driving frequency, for various values of ß. [You may assume that wo = 1 rad/s, or equivalently you can choose to measure driving frequency w and damping ß as fractions or multiples of wo. Choose a convenient value for the driving force.]

icon
Related questions
Question
Problem 5: (a) For a driven, damped harmonic oscillator, the peak of the amplitude
(and therefore the maximum potential energy) occurs for a driving frequency of w=w₂ =
√3 - 2/3². Determine the driving frequency at which the kinetic energy of the system is
a maximum. (b) Make a "resonance peak" plot of kinetic energy versus driving frequency,
for various values of ß. [You may assume that wo = 1 rad/s, or equivalently you can choose
to measure driving frequency w and damping / as fractions or multiples of wo. Choose a
convenient value for the driving force.]
Transcribed Image Text:Problem 5: (a) For a driven, damped harmonic oscillator, the peak of the amplitude (and therefore the maximum potential energy) occurs for a driving frequency of w=w₂ = √3 - 2/3². Determine the driving frequency at which the kinetic energy of the system is a maximum. (b) Make a "resonance peak" plot of kinetic energy versus driving frequency, for various values of ß. [You may assume that wo = 1 rad/s, or equivalently you can choose to measure driving frequency w and damping / as fractions or multiples of wo. Choose a convenient value for the driving force.]
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 4 images

Blurred answer