Problem 4. Consider the logistic growth equation dy = ky (1 – 4) dt (a) Differentiate this equation with respect to t, and use the chain rule to show that any solution y satisfies the second-order ODE - Py (1 - %) (1 - ) dt2 (b) Show that the graph of a solution y(t) is concave up if 0 < y < A/2 and concave down if A/2 < y < A. 1 (c) Suppose a population obeys this logistic differential equation and y(0) = yo < A/2. Use Part (b) to find the time t when the population is growing fastest.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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part a,b and part c.

Problem 4. Consider the logistic growth equation
dy
= ky (1-)
%3D
dt
(a) Differentiate this equation with respect to t, and use the chain rule to show that any solution y satisfies the
second-order ODE
d²y
2y
dt2
A
(b) Show that the graph of a solution y(t) is concave up if 0 < y < A/2 and concave down if A/2 < y < A.
1
(c) Suppose a population obeys this logistic differential equation and y(0) = yo < A/2. Use Part (b) to find the
time t when the population is growing fastest.
Transcribed Image Text:Problem 4. Consider the logistic growth equation dy = ky (1-) %3D dt (a) Differentiate this equation with respect to t, and use the chain rule to show that any solution y satisfies the second-order ODE d²y 2y dt2 A (b) Show that the graph of a solution y(t) is concave up if 0 < y < A/2 and concave down if A/2 < y < A. 1 (c) Suppose a population obeys this logistic differential equation and y(0) = yo < A/2. Use Part (b) to find the time t when the population is growing fastest.
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