Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan Mass of Soil Retained (g) 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5

Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan Mass of Soil Retained (g) 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question 42 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 88 No. 10 2.000 69 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 43 No. 100 0.150 19 No. 200 0.075 9. Characteristics of No. 40 Fraction LL PL General classification Granular materials (35% or less of total sample passing No. 200) A-1 A-2 Group classification A-1-a A-1-b A-3 A-2-4 A-2-5 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 50 max. No. 40 No. 200 30 max. 15 max. 50 max. 25 max 51 min. 10 max. 35 max. 35 max. 35 max 35 max. Characteristics of fraction passing No. 40 Liquid limit. Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max NP 10 max. 10 max. 11 min. 11 min. Usual types of significant constituent Stone fragments. gravel, and sand Fine Silty or clayey gravel and sand sand materials SUS F1 F2 F3 F4 FS F6 F7 F8 24 4 % & 5 R Y 因

The dry weight of sample = 1kg. Result of sieve analysis are shown below. Sieve Size Weight retained (g) 4.65 mm 0 2.46 mm 100 1.98 mm 250 0.30 mm 350 0.10 mm. 200 0.5 mm 100 Determine the Fineness Modulus.
In the table below, find the missing values for pure sand sample and without fine materials ote (weight of sample 1000g). Sieve opening (mm) Retained weight Retained weight% Cumulative percentage Passing% 4.75 2.36 100 10 90 1.18 X X 0.6 250 25 50 0.3 200 20 30 0.15 10 Pan
The result from the sieve analysis is shown: Calculate the coefficient of uniformity. Determine the percentage of sand? What is the effective size of the sample (in mm).
Give me right solution with clear calculations.
Determine the percentage of the following types of soil in the sample;
Problem The following are the results of a sieve analysis: a. Determine the percent finer than each sieve and plot a grain- size distribution curve. b. Determine D10, D30, and D60 from the grain-size distribution curve. c. Calculate the uniformity coefficient, C. the coefficient of gradation, Co. U.S. sieve no. 4 10 20 40 60 80 100 200 Pan Mass of soil retained (g) 0 44 56 82 51 106 92 85 35
A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58. The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by AASHTO system.Justify your answer. a. A-5 (6) b. A-6 (5) c. A-7-6 (20) d. A-4 (5)
QUESTION 1 1. For a soil with De=0.41 mm, D = 0.22mm, and Die = 0.08 mm, calculate the uniformity coefficient and the coefficient of gradation. 2. The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer 40 80 170 200 0.04 mm 0.015 mm 0.008 mm 0.004 mm 0.002 mm Draw the grain-size distribution curve. Percent finer 100 97 74 27 11 a) b) Determine the percentages of gravel, sand, silt and clay according to the AASHTO system.
Quèstion 2 The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 61 PL 26 Determine its classification using USCS.
Answer in three decimal places please
Question 1 The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 89 4 4.760 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 40 60 0.250 31 100 0.149 20 200 0.074 4 LL 60 PL 40 Determine its classification using USCS.