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PROBLEM 3 The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameter P = 100 + (ECD) x 0.1 Q = 100 + (BAC) x 0.1 0 = 30 x (P/Q) 2a HE A = 0, B=5, C = 4, D = 8, E = 7 P = 100 + (748) x 0.1 = 174.8 kN Q = 100+ (504) x 0.1 = 150.4 kN 0 30 x (174.8/150.4) = 34.87° = 9 2a

PROBLEM 3 The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameter P = 100 + (ECD) x 0.1 Q = 100 + (BAC) x 0.1 0 = 30 x (P/Q) 2a HE A = 0, B=5, C = 4, D = 8, E = 7 P = 100 + (748) x 0.1 = 174.8 kN Q = 100+ (504) x 0.1 = 150.4 kN 0 30 x (174.8/150.4) = 34.87° = 9 2a

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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  • Do not round off intermediate values when using them to solve subsequent values; however, they 
    may be written up to 4 decimal places in the answer sheets. Final answers should be rounded off 
    up to 4 DECIMAL PLACES.
  • Box the final answers. 
PROBLEM 3 The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameter P = 100 + (ECD) x 0.1 Q = 100 + (BAC) x 0.1 0 = 30 x (P/Q) Fo 2a B O P = 100+ (748) x 0.1 = 174.8 kN Q = 100 + (504) x 0.1 = 150.4 kN 0 = 30 x (174.8/150.4) = 34.87° G HE A = 0, B=5, C = 4, D = 8, E = 7 0 2a
Transcribed Image Text:PROBLEM 3 The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameter P = 100 + (ECD) x 0.1 Q = 100 + (BAC) x 0.1 0 = 30 x (P/Q) Fo 2a B O P = 100+ (748) x 0.1 = 174.8 kN Q = 100 + (504) x 0.1 = 150.4 kN 0 = 30 x (174.8/150.4) = 34.87° G HE A = 0, B=5, C = 4, D = 8, E = 7 0 2a
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