Problem 3: The foil shielding on a power cable, carrying a DC current I = 0.39 A, has broken off. The unshielded part of the wire is x 0.021 meters long. The shielded parts of the wire do not contribute to the magnetic field outside the wire. Point P is above the right-hand end of the unshielded section, a distance x/2 above the wire. The current flows to the right (in the positive direction) as shown. The small length of wire, dl, a distance l from the midpoint of the unshielded section of the wire, contributes a differential magnetic field dB at point P. Ignore any edge effects. Part (a) Input an expression for the magnitude of the differential magnetic field, dB, generated at point P by the current moving through the segment of wire dl in terms of given parameters and fundamental constants. SchematicChoice : Holdl Holldl Holxdl dB = dB dB 3 8nx (() + 12 2nx + 1² + Holxdl Holxdl dB dB %3D %D 8nl () + 1² ) 2 4п + 1? Part (b) Perform the indefinite integral from part a. SchematicChoice : Holdl Holxl Holxl B = B = B = 1/2 1/2 2mx () (21 + 27 () + 1²) 8πί Holl B = 1/2 2πχ + Part (c) Select the limits of integration that will correctly calculate the magnetic field at P due to the current in the unshielded length of wire. MultipleChoice : 1) l = -00 to l = 0 2) l = -x to l = x 3) 1 = 0 to l = 00 4) l = -x to l = 0 5) l = -00 to l = 0 6) 1 = -x/2 to l= x/2 ミニ