2 (1)w - 0 -1 -2 2 3 20 20 10 0 -10 t [seconds] 5 6 7 × 10 8 -20 0 1 2 3 4 5 6 7 8 t [seconds] ×104 Hint: Below please find the table of Bessel function values as below. TABLE 4.1 TABLE OF BESSEL FUNCTION VALUES n B=0.1 B = 0.2 B = 0.5 B=1 B=2 B=5 B=8 B=10 0 0.997 0.990 0.938 0.765 0.224 -0.178 0.172 -0.246 1 0.050 0.100 0.242 0.440 0.577 -0.328 0.235 0.043 2 0.001 0.005 0.031 0.115 0.353 0.047 -0.113 0.255 3 0.020 0.129 0.365 -0.291 0.058 4 0.002 0.034 0.391 -0.105 -0.220 5 0.007 0.261 0.186 -0.234 6 0.001 0.131 0.338 -0.014 7 0.053 0.321 0.217 8 9 10 11 12 13 14 15 16 0.018 0.223 0.318 0.006 0.126 0.292 0.001 0.061 0.207 0.026 0.123 0.010 0.063 0.003 0.029 0.001 0.012 0.004 0.001 Problem 3: angle modulation) (a) The message m(t) and the FM-modulated signal u(t) are both given on next page. Determine the maximum frequency deviation and the carrier frequency. Note: don't overlook the 10+ factor on the "t" axis. (b) Determine the average power of the modulated signal in (a). (c) If the message is now m(t) = 25 cos(271000t), the carrier frequency is 98.9 MHz, and the constant k = 40, compute the bandwidth of the new FM signal. (d) The carrier amplitude is A. = 20.The FM signal in part (c) has frequency components at fc, fc±fm, fc±2fm, fc±3fm, etc. Compute the power of the spectral components at fc, fc-fm, and fc+fm, and its power percentage in the total FM signal's power.
2 (1)w - 0 -1 -2 2 3 20 20 10 0 -10 t [seconds] 5 6 7 × 10 8 -20 0 1 2 3 4 5 6 7 8 t [seconds] ×104 Hint: Below please find the table of Bessel function values as below. TABLE 4.1 TABLE OF BESSEL FUNCTION VALUES n B=0.1 B = 0.2 B = 0.5 B=1 B=2 B=5 B=8 B=10 0 0.997 0.990 0.938 0.765 0.224 -0.178 0.172 -0.246 1 0.050 0.100 0.242 0.440 0.577 -0.328 0.235 0.043 2 0.001 0.005 0.031 0.115 0.353 0.047 -0.113 0.255 3 0.020 0.129 0.365 -0.291 0.058 4 0.002 0.034 0.391 -0.105 -0.220 5 0.007 0.261 0.186 -0.234 6 0.001 0.131 0.338 -0.014 7 0.053 0.321 0.217 8 9 10 11 12 13 14 15 16 0.018 0.223 0.318 0.006 0.126 0.292 0.001 0.061 0.207 0.026 0.123 0.010 0.063 0.003 0.029 0.001 0.012 0.004 0.001 Problem 3: angle modulation) (a) The message m(t) and the FM-modulated signal u(t) are both given on next page. Determine the maximum frequency deviation and the carrier frequency. Note: don't overlook the 10+ factor on the "t" axis. (b) Determine the average power of the modulated signal in (a). (c) If the message is now m(t) = 25 cos(271000t), the carrier frequency is 98.9 MHz, and the constant k = 40, compute the bandwidth of the new FM signal. (d) The carrier amplitude is A. = 20.The FM signal in part (c) has frequency components at fc, fc±fm, fc±2fm, fc±3fm, etc. Compute the power of the spectral components at fc, fc-fm, and fc+fm, and its power percentage in the total FM signal's power.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
![2
(1)w
-
0
-1
-2
2
3
20
20
10
0
-10
t [seconds]
5
6
7
× 10
8
-20
0
1
2
3
4
5
6
7
8
t [seconds]
×104
Hint: Below please find the table of Bessel function values as below.
TABLE 4.1 TABLE OF BESSEL FUNCTION VALUES
n
B=0.1
B = 0.2
B = 0.5
B=1 B=2 B=5
B=8
B=10
0
0.997
0.990
0.938
0.765
0.224
-0.178
0.172
-0.246
1
0.050
0.100
0.242
0.440 0.577
-0.328
0.235
0.043
2
0.001
0.005
0.031
0.115
0.353
0.047
-0.113
0.255
3
0.020
0.129
0.365
-0.291
0.058
4
0.002
0.034
0.391
-0.105
-0.220
5
0.007
0.261
0.186
-0.234
6
0.001
0.131
0.338
-0.014
7
0.053
0.321
0.217
8
9
10
11
12
13
14
15
16
0.018
0.223
0.318
0.006
0.126
0.292
0.001
0.061
0.207
0.026
0.123
0.010
0.063
0.003
0.029
0.001
0.012
0.004
0.001](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc231fac6-f61a-45b2-b174-05bc9b27b74a%2F6c27e59b-e182-406e-a5d3-9a0691120716%2Fi0291g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2
(1)w
-
0
-1
-2
2
3
20
20
10
0
-10
t [seconds]
5
6
7
× 10
8
-20
0
1
2
3
4
5
6
7
8
t [seconds]
×104
Hint: Below please find the table of Bessel function values as below.
TABLE 4.1 TABLE OF BESSEL FUNCTION VALUES
n
B=0.1
B = 0.2
B = 0.5
B=1 B=2 B=5
B=8
B=10
0
0.997
0.990
0.938
0.765
0.224
-0.178
0.172
-0.246
1
0.050
0.100
0.242
0.440 0.577
-0.328
0.235
0.043
2
0.001
0.005
0.031
0.115
0.353
0.047
-0.113
0.255
3
0.020
0.129
0.365
-0.291
0.058
4
0.002
0.034
0.391
-0.105
-0.220
5
0.007
0.261
0.186
-0.234
6
0.001
0.131
0.338
-0.014
7
0.053
0.321
0.217
8
9
10
11
12
13
14
15
16
0.018
0.223
0.318
0.006
0.126
0.292
0.001
0.061
0.207
0.026
0.123
0.010
0.063
0.003
0.029
0.001
0.012
0.004
0.001
Transcribed Image Text:Problem 3:
angle modulation)
(a) The message m(t) and the FM-modulated signal u(t) are both given on next page. Determine the maximum
frequency deviation and the carrier frequency. Note: don't overlook the 10+ factor on the "t" axis.
(b) Determine the average power of the modulated signal in (a).
(c) If the message is now m(t) = 25 cos(271000t), the carrier frequency is 98.9 MHz, and the constant k = 40,
compute the bandwidth of the new FM signal.
(d) The carrier amplitude is A. = 20.The FM signal in part (c) has frequency components at fc, fc±fm, fc±2fm, fc±3fm,
etc. Compute the power of the spectral components at fc, fc-fm, and fc+fm, and its power percentage in the total FM
signal's power.
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