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Problem 3: An FM signal s(t) = 100 cos(2л f¸t+40 √ m(t)dt),With m(t) =| 10】 40′ [10Σ II(ª¯”) –10 Σ II 00 00 -4n. t-4n-2 ПI (a) (b) 2 12--00 Determine the peak-frequency deviation and the peak-phase deviation. Sketch m(t) and the instantaneous frequency as a function of time, given f. =1000Hz. 2 ³¹)]u(t). =-00

Problem 3: An FM signal s(t) = 100 cos(2л f¸t+40 √ m(t)dt),With m(t) =| 10】 40′ [10Σ II(ª¯”) –10 Σ II 00 00 -4n. t-4n-2 ПI (a) (b) 2 12--00 Determine the peak-frequency deviation and the peak-phase deviation. Sketch m(t) and the instantaneous frequency as a function of time, given f. =1000Hz. 2 ³¹)]u(t). =-00

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Problem 3: An FM signal s(t) = 100 cos(2л f¸t+40 √ m(t)dt),With m(t) =| 10】 40′ [10Σ II(ª¯”) –10 Σ II 00 00 -4n. t-4n-2 ПI (a) (b) 2 12--00 Determine the peak-frequency deviation and the peak-phase deviation. Sketch m(t) and the instantaneous frequency as a function of time, given f. =1000Hz. 2 ³¹)]u(t). =-00
Transcribed Image Text:Problem 3: An FM signal s(t) = 100 cos(2л f¸t+40 √ m(t)dt),With m(t) =| 10】 40′ [10Σ II(ª¯”) –10 Σ II 00 00 -4n. t-4n-2 ПI (a) (b) 2 12--00 Determine the peak-frequency deviation and the peak-phase deviation. Sketch m(t) and the instantaneous frequency as a function of time, given f. =1000Hz. 2 ³¹)]u(t). =-00
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