Problem-3:A ball of mass 200 gram strikes a wall perpendicular to its surface at a speed of 10 m/s andrebounds back at the speed of 5 m/s. It is in contact with the wall for 2 milli-sec. Find theaverage force exerted by the wall on the ball.

Name: Problem-3:A ball of mass 200 gram strikes a wall perpendicular to its
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Description: Problem-3:A ball of mass 200 gram strikes a wall perpendicular to its surface at a speed of 10 m/s andrebounds back at the speed of 5 m/s. It is in contact with the wall for 2 milli-sec. Find theaverage force exerted by the wall on the ball.

Average force exerted will be calculated as follows: F=Pf-Pit F is the average force Pf and Pi are…

Answered: Problem-3: A ball of mass 200 gram…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem-3:
A ball of mass 200 gram strikes a wall perpendicular to its surface at a speed of 10 m/s and
rebounds back at the speed of 5 m/s. It is in contact with the wall for 2 milli-sec. Find the
average force exerted by the wall on the ball.

Expert Solution

Step 1

Average force exerted will be calculated as follows:

$F = \frac{P_{f} - P_{i}}{t}$

F is the average force

$P_{f} a n d P_{i}$ are the final and initial momentum

Say direction towards the wall is positive and away from the wall is negative.

Therefore,

$P_{i} = + m v_{i} = + (200 \times 10^{- 3}) \times 10 = + 2 K g m / s$

$P_{f} = - m v_{f} = - (200 \times 10^{- 3}) \times 5 = - 1 K g m / s$

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