Find the heat capacity of the hot and cold fluid. PROALEM # 22.a.massat a pressure= 2at m and flow rate = 1020 kg /min,the temperature of hot water isbeing dicreared fomusing a heat exchanger.w coolant with248.09°F to 212.09 oFReservoir waterU wsed asmass flow rate = 1800 ka lmin and= 50.09 oF.The minimum = 270. 17 ft"of heat ex changerin let temperatureallow able surface are a2.%3Dall ow able overall heat = 206.05 btu/Thetransfer coefficient of heat exchangermaxi muim%3DThe heat Capaci ty to be use d must bethe average valueofinlet and outlet temperatures.

Answered: Image /qna-images/answer/e396195f-c1da-47c9-8d28-8758492fdd57.jpg

PROBLEM # 22.a. mass = 2at m and flow rate = 1020 kg /min, decreased from at a pressure= the temperature of hot water is being 212.09 OF using a heat coolant with 248.09 °F to exchanger. Reservvir water u used as and mass flow rate = 1800 kg Imin inlet temperature = 50. 04 °F. The minimum allow able surface are a = 2 70. 17 ft" %3D of heat ex changer maxi mum all ow able overall heat = 2016.05 btu/ The transfer The heat Capaci ty to be use d must be the average value of coefficient of heat exchanger inet and outlet temperatures.

PROBLEM # 22.a. mass = 2at m and flow rate = 1020 kg /min, decreased from at a pressure= the temperature of hot water is being 212.09 OF using a heat coolant with 248.09 °F to exchanger. Reservvir water u used as and mass flow rate = 1800 kg Imin inlet temperature = 50. 04 °F. The minimum allow able surface are a = 2 70. 17 ft" %3D of heat ex changer maxi mum all ow able overall heat = 2016.05 btu/ The transfer The heat Capaci ty to be use d must be the average value of coefficient of heat exchanger inet and outlet temperatures.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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