Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. The moment of inertia of a disk about its center is I = (1/2)MR². (a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and passing through its center? (b) What is the angular acceleration of the disk? 11.9 N 0.350 m 40.0 14.6 N 8.50 N

Principles of Physics: A Calculus-Based Text
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Chapter10: Rotational Motion
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Problem 56P: A student sits on a freely rotating stool holding two dumbbells, each of mass 3.00 kg (Fig. P10.56)....
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Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure
below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle
with the radius. The moment of inertia of a disk about its center is I = (1/2)MR².
(a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and
passing through its center?
(b) What is the angular acceleration of the disk?
11.9 N
0.350 m
40.0° 14.6 N
8.50 N
Transcribed Image Text:Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. The moment of inertia of a disk about its center is I = (1/2)MR². (a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and passing through its center? (b) What is the angular acceleration of the disk? 11.9 N 0.350 m 40.0° 14.6 N 8.50 N
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