Problem 2: The current loop shown in the figure below has a current I = 10 A. The current loop is in a constant magnetic field B = Bĵ, where B = 1.5 T. Show that the net magnetic force on the current loop is 0. Answer: Fnet = Fseg,1 + Fseg,2 + Fseg,3 + Fseg,4 = 1.5k + 0.6k − 1.5k – 0.6k = 0 B / = 10A Segment 3 Segment 2 0.08 m Segment 4 Segment 1 0.10 m- 60° +

A single ionized atom, that is deficient one electron, is traveling at in a straight line when it enters a uniform magnetic field of strength 0.750 T. The ion is traveling in the plane of the page, while the magnetic field points into the page. (See the diagram below.) If the mass of the ionized atom is 6.68 x 10-27 kg, what is the frequency in Hz of the resultant circular motion? The charge of a single electron is 1.602 x 10-19 C.     a. 7.47 MHz   b. 6.33 MHz   c. 4.13 MHz   d. 3.50 MHz   e. .2.86 MHz

The cube in the figure is 30.0 cm on the edge. Four straight segments of wire - ab, bc, cd, and da - form a closed loop that carries a current I = 4.50 A in the direction shown. A uniform B = 0.078 T is in the negative z-direction.   1. Determine the magnitude of the magnetic force on segment ab. 2. The direction of the magnetic force on segment ab is 3. Determine the magnitude of the magnetic force on segment bc. 4. The direction of the magnetic force on segment bc is 5. Determine the magnitude of the magnetic force on segment cd. 6. The direction of the magnetic force on segment cd is 7. Determine the magnitude of the magnetic force on segment da. 8. The direction of the magnetic force on segment cd is

A wire of length = 0.35 m is conducting a current of i = 7.5 A toward the top of the page and through a B = 3.0 T uniform magnetic field directed into the page, as shown in the figure. What is the magnitude F of the magnetic force on the wire? F = What is the direction of the magnetic force on the wire? ОО left into the screen up right down out of the screen N B