Problem 2 The beam subjected to a uniformly distributed load of 300 N/m is suspended by a cable-pulley system, as shown in Fig.2. (a) Determine the reactions at support A and the force in the cable. (b) Plot the moment distribution of the beam. (c) Plot the shear distribution of the beam. C E D 45° F B |-1.5m--1.5m--1.5m--1.5 m- Fig. 2 300 N/m

275 N 1600 N 0.5 1.5 m 1.8 m Situation 4. The frame shown with a braked pulley is acted upon by four forces. If the resultant of the forces passes through point A A. 14. Determine the magnitude of the unknown tension T2. c. 877.885 N 1.25 m B. a. 785.996 N b. 846.559 N d. 731.792 N 50° 15. Determine the magnitude and direction of the resultant force R. a. R= 564.299 N, OR = 0.254° b. R= 797.831 N, OR = 54.702° d. R= 829.067 N, OR = 14.383°7 0.6 m c. R= 685.914 N, OR = 75.617°À T2 650 N

3. Determine the moment at each support of the continuous beam shown. Make at least five distributions. Use Moment Distribution method a 130 kN CS Scanned with CamScanner -3.0m-3.0m-3.0m b -21- -I 25 kN/m -5.0 m -21- d 50 kN -2.5 m-2.5 m-

Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and shear-force diagram are provided. M-37 kip-ft EP-16 kips By-26.56 kips C,-61.44 kips 8 kips/ft M B 3 ft 9 ft 3 ft B, • 0. B,- 72 sdp sun

3/54 The horizontal steel shaft has a mass of 480 kg and is suspended by a vertical cable from A and by a second cable BC which lies in a vertical transverse plane and loops un- derneath the shaft. Calculate the tensions T₁ and T₂ in the cables. 1.5 m 1.5 m A x y T₂ 3 m. 1 N B T2 T₁ 4 m. PROBLEM 3/54 1m 3 m

TOS1 Part 1- Shear and Moment Diagram Using the shear and moment diagram, determine the location of the maximum moment 180 kN 67.5 kN Hinge D E F B C 3m--3 m - 3 m-E5 m + 3m | = 2080 × 10mn | = 1040 × 10^mn° E = 200 GPa O point B O point C O point D O point E

Draw the shear and bending moment curves for the beam and loading and the maximum absolute value of the shear and bending moment in the beam by the semi-graphical method. SHOW SOLUCION. 24 kN 24 kN 29 kN/m A B |D -1.5 m--1.5 m -1.5 m |

Analyze the continuous beam on the photo. Please show how to draw the shear, moment diagrams and the elastic curve.

Problem 3. Draw the shear and Bending Moment Diagram of the beam shown. Solve the problem using Moment Distribution Method A P/2 a/2 L2 P a W 39.5kN/m B P 118.50KN W L1 a 3.60m - → L1 7.10m L2 6.10m

What is the Maximum moment in kN-m. Given: w1 44, w2 17, a 3, b 4, and c 3. %3D %3D w1 kN/m w2 kN/m D A B a m b m cm