PROBLEM 2: A reinforced concrete beam has a simple span of 7m. It carries a uniformly distributed dead load (including its own weight) of 9kN/m, live load equal to 18KN/m. The beam is reinforced with 3D28mm bars and has a width of 250mm and an effective depth of 450mm. fc'=28Mpa and fy=345Mpa. 1. Using the simplified calculation for Vc, what is the nominal shear capacity of concrete? 2. At what section of the beam is the web reinforcement theoretically not required?

Rectangular reinforced concrete beam section b = 40 cm, h = 60 cm, d = 53 cm, material strength fy = 4200 = 4200 kgf / cm^2, fc ' = 280 kgf/cm^2, beam section configuration #4 For closed stirrups @15 cm, the net cover is 4 cm, and the beam section is subjected to a torque of Tu = Tcr. Q: What is the ultimate shear load value Vu that the beam section can bear. Among them, Tcr is the cracking torque of the beam section, #4 steel bar (db=1.27 cm, Ab=1.267 cm^2).

1000 N/m Given: A cantilever beam has loading and cross section as shown. The allowable stress is 64 MPa. 150 mm Determine: the minimum width for the beam 6 m b

Q. A simply supported beam is carrying a uniformly distributed and a gradient distributed loads as shown in Figure 1. Given that the maximum shearing stress is 270 MPa, determine the value of w. o kN/m |C -1.7m --1.7m 3.2m 170 mm Romm 37mm - 37 mm Figure 1